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SVETLANKA909090 [29]
4 years ago
10

2H2 +O2 = 2H2O balance equation with 5 oxygen

Chemistry
1 answer:
Ivenika [448]4 years ago
5 0

10H₂    +   5O₂ →    10H₂O

Explanation:

This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:

   "In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".

This meaning of this is that; the number of atoms on each side of the expression must be the same.

                    2H₂    +   O₂ →    2H₂O

let us check is the equation above is balanced;

   

                                      2H₂    +   O₂ →    2H₂O

Elements             reactant                product

H                                  4                           4

O                                   2                           2

We can see vividly that the equation is balanced;

Now; if we have 5 oxygen gas, we multiply the equation through by 5:

 

                                 5 x          (  2H₂    +   O₂ →    2H₂O   )

     ⇒        10H₂    +   5O₂ →    10H₂O

Elements             reactant                product

H                                  20                       20

O                                  10                        10

learn more:

Balanced equation brainly.com/question/11102790

#learnwithBrainly

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Natasha_Volkova [10]

Answer:

<em>The combined law is:</em>

          \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

See the derivation below.

Explanation:

<em><u>1. Boyle's law:</u></em>

    PV=constant\\\\P_1V_1=P_2V_2

<em />

<u><em>2. Charles' law:</em></u>

        \dfrac{V}{T}=constant\\\\\\\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

<em><u>3. Gay-Lussac’s law</u></em>

      \dfrac{P}{T}=constant\\\\\\\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

<u>4. Summary:</u>

  •    PV = K
  •    V/T = K'
  •    P/T = K''

Mulitply PV by V/T and P/T

        PV\times \dfrac{V}{T}\times \dfrac{P}{T}=K\times K'\times K''\\\\\\\dfrac{P^2V^2}{T^2}=constant\\\\\\\sqrt{\dfrac{P^2V^2}{T^2}}=\sqrt{constant}\\\\\\\dfrac{PV}{T}=constant

Thus:

          \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

Which is<em> the combined law.</em>

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Answer:

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Explanation:

The combustion reaction of balanced butane (C₄H₁₀) is as follows:

2 C₄H₁₀ + 13 O₂ ⇒ 8 CO₂ + 10 H₂O

The amount of butane molecules can be transferred to moles to establish the stoichiometric relationship with water and calculate the moles of water that are formed:

6.02x10²³ molecules _____ 1 mol of butane

1.2x10²⁶ molecules _____ X = 199.34 moles of butane

<em>Calculation</em>: 1.2x10²⁶ molecules x 1 mol / 6.02x10²³ molecules = 199.34 moles of butane

According to the balanced equation:

2 moles butane _____ 10 moles of water

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And now, you can calculate the mass of the amount of moles obtained from water:

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