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SVETLANKA909090 [29]
4 years ago
10

2H2 +O2 = 2H2O balance equation with 5 oxygen

Chemistry
1 answer:
Ivenika [448]4 years ago
5 0

10H₂    +   5O₂ →    10H₂O

Explanation:

This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:

   "In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".

This meaning of this is that; the number of atoms on each side of the expression must be the same.

                    2H₂    +   O₂ →    2H₂O

let us check is the equation above is balanced;

   

                                      2H₂    +   O₂ →    2H₂O

Elements             reactant                product

H                                  4                           4

O                                   2                           2

We can see vividly that the equation is balanced;

Now; if we have 5 oxygen gas, we multiply the equation through by 5:

 

                                 5 x          (  2H₂    +   O₂ →    2H₂O   )

     ⇒        10H₂    +   5O₂ →    10H₂O

Elements             reactant                product

H                                  20                       20

O                                  10                        10

learn more:

Balanced equation brainly.com/question/11102790

#learnwithBrainly

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Picric acid has been used in the leather industry and in etching copper. However, its laboratory use has been restricted because
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Answer:

0.3023 M

Explanation:

Let Picric acid = H_{picric}

So,  H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

The ICE table can be given as:

                          H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

Initial:                0.52                                               0                  0

Change:             - x                                                 + x                 + x

Equilibrium:      0.52 - x                                        + x                 + x

Given that;

acid dissociation constant  (K_a) = 0.42

K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}

0.42 = \frac{[x][x]}{0.52-x}}

0.42 = \frac{[x]^2}{0.52-x}}

0.42(0.52-x) = x²

0.2184 - 0.42x = x²

x²  + 0.42x - 0.2184 = 0                   -------------------- (quadratic equation)

Using the quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}    ;     ( where +/-  represent ± )

= \frac{-0.42+/-\sqrt{(0.42)^2-4(1)(-0.2184)} }{2*1}

= \frac{-0.42+/-\sqrt {0.1764+0.8736} }{2}

= \frac{-0.42+\sqrt {1.0496} }{2}     OR   \frac{-0.42-\sqrt {1.0496} }{2}

= \frac{-0.42+1.0245}{2}       OR    \frac{-0.42-1.0245}{2}

= \frac{0.6045}{2}                 OR    -\frac{1.4445}{2}

= 0.30225          OR     - 0.72225

So, we go by the +ve integer that says:

x =  0.30225

x = [ H_3}O^+ ] = [   Picric^- ] =  0.3023  M

∴  the value of  [H3O+] for an 0.52 M solution of picric acid  = 0.3023 M     (to 4 decimal places).

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3 years ago
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