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SVETLANKA909090 [29]
4 years ago
10

2H2 +O2 = 2H2O balance equation with 5 oxygen

Chemistry
1 answer:
Ivenika [448]4 years ago
5 0

10H₂    +   5O₂ →    10H₂O

Explanation:

This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:

   "In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".

This meaning of this is that; the number of atoms on each side of the expression must be the same.

                    2H₂    +   O₂ →    2H₂O

let us check is the equation above is balanced;

   

                                      2H₂    +   O₂ →    2H₂O

Elements             reactant                product

H                                  4                           4

O                                   2                           2

We can see vividly that the equation is balanced;

Now; if we have 5 oxygen gas, we multiply the equation through by 5:

 

                                 5 x          (  2H₂    +   O₂ →    2H₂O   )

     ⇒        10H₂    +   5O₂ →    10H₂O

Elements             reactant                product

H                                  20                       20

O                                  10                        10

learn more:

Balanced equation brainly.com/question/11102790

#learnwithBrainly

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The equations given in the problem introduction can be added together to give the following reaction: overall: N2O4→2NO2 However
Murljashka [212]

Answer:

Reverse the 2 NO_2 \longrightarrow 2 NO + O_2  reaction

Explanation:

Reactions:

2 NO_2 \longrightarrow 2 NO + O_2

N_2O_4 \longrightarrow 2 NO + O_2

Overall:

N_2O_4 \longrightarrow 2 NO_2

As can be seen, in the overall reaction we have N_2O_4 in the reactants like in the second reaction and NO_2 in the products. The NO_2 is in the first reaction but as a reactant so we need to reverse that reaction:

2 NO + O_2 \longrightarrow 2 NO_2

N_2O_4 \longrightarrow 2 NO + O_2

Combining:

N_2O_4 + 2 NO + O_2\longrightarrow 2 NO + O_2 + 2 NO_2

N_2O_4 \longrightarrow 2 NO_2

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Describe the pattern of the lewis dot structure of the first 18 elements
posledela

Explanation: Lewis dot structures are the structures which represent the valence electrons of an atom. The dots in the structure are considered as the valence electrons.

First 18 elements of the periodic table are Hydrogen(H), Helium (He), Lithium (Li), Beryllium (Be), Boron (B), Carbon (C), Nitrogen (N), Oxygen (O), Fluorine (F), Neon(Ne), Sodium (Na), Magnesium (Mg), Aluminium (Al), Silicon (Si), Phosphorous (P), Sulfur (S), Chlorine (Cl) and Argon(Ar).

The valence electrons are the electrons which are present in the outermost shell of an atom. The electronic configuration of the elements are:

Hydrogen (H) = 1s^1 ; Valence electrons = 1

Helium (He) = 1s^2 ; Valence electrons = 2

Lithium (Li) = 1s^22s^1 ; Valence electrons = 1

Beryllium (Be) = 1s^22s^2 ; Valence electrons = 2

Boron (B) = 1s^22s^22p^1 ; Valence electrons = 3

Carbon (C) = 1s^22s^22p^2 ; Valence electrons = 4

Nitrogen (N) = 1s^22s^22p^3 ; Valence electrons = 5

Oxygen (O) = 1s^22s^22p^4 ; Valence electrons = 6

Fluorine (F) = 1s^22s^22p^5 ; Valence electrons = 7

Neon (Ne) = 1s^22s^22p^6 ; Valence electrons = 8

Sodium (Na) = 1s^22s^22p^63s^1 ; Valence electrons = 1

Magnesium (Mg) = 1s^22s^22p^63s^2 ; Valence electrons = 2

Aluminium (Al) = 1s^22s^22p^63s^23p^1 ; Valence electrons = 3

Silicon (Si) = 1s^22s^22p^63s^23p^2 ; Valence electrons = 4

Phosphorous (P) = 1s^22s^22p^63s^23p^3 ; Valence electrons = 5

Sulfur (S) = 1s^22s^22p^63s^23p^4 ; Valence electrons = 6

Chlorine(Cl) = 1s^22s^22p^63s^23p^5 ; Valence electrons = 7

Argon (Ar) = 1s^22s^22p^63s^23p^6 ; Valence electrons = 8

  • Elements hydrogen and helium belong to period 1 of the period table, so the lewis dot structures will have maximum of 2 electrons
  • Elements from lithium to neon belong to period 2 and the lewis dot structures will have maximum of 8 electrons.
  • Elements from sodium and argon belong to the period 3 of the periodic table, and will have maximum of 8 electrons in their lewis dot structures.

Lewis dot structures are attached below.

6 0
3 years ago
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