Express the following numbers in Standard Form:

Enter your answer in the provided box. the ph of a bicarbonate-carbonic acid buffer is 7.06. calculate the ratio of the concentr

Marina CMI [18]

The ratio would be 12.6 of carbon acid

7 0

3 years ago

chemistry A basketball is inflated to a pressure of 1.10 atm in a 28.0°C garage. What is the pressure of the basketball outside

butalik [34]

Answer : The final pressure of the basketball is, 0.990 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$

or,

$\frac{P_1}{P_2}=\frac{T_1}{T_2}$

where,

$P_1$ = initial pressure = 1.10 atm

$P_2$ = final pressure = ?

$T_1$ = initial temperature = $28.0^oC=273+28.0=301.0K$

$T_2$ = initial temperature = $-2.00^oC=273+(-2.00)=271.0K$

Now put all the given values in the above equation, we get:

$\frac{1.10atm}{P_2}=\frac{301.0K}{271.0K}$

$P_2=0.990atm$

Thus, the final pressure of the basketball is, 0.990 atm

7 0

2 years ago

2 attempts left Click the "draw structure" button to launch the drawing utility. Draw one product formed when the following dien

Yuliya22 [10]

Answer:

2-chloro-1-methyl-cyclohex-1,4-diene.

Explanation:

Hello,

In this case, the addition of hydrochloric acid acts as an electrophilic atack in which the hydrogen bonded to the double-bonded carbon connected to the carbon with the methyl substitution is substituted by the chlorine from the hydrochloric acid, in such a way, 2-chloro-1-methyl-cyclohex-1,4-diene is produced as one equivalent of HCl is used therefore one substitution will be attained for chlorine, and hydrogen as a side product as shown on the attached picture.

Best regards.

7 0

2 years ago

Find the pH of the equivalence point and the volume (mL) of 0.0372 M NaOH needed to reach the equivalence point in the titration

elixir [45]

Answer:

8.54

Explanation:

At equivalence point :

42.2 X 0.052 = Vol. NaOH X 0.0372

Vol of NaOH = 2.1944/0.0372 = 58.99 ml

So volume of NaOH recquired to reach equivalence point = 58.99 ml

Number of miliimoles of CH3COOH = molarity X volume in ml = 42.2 X 0.052 = 2.1944 millimoles

Number of millimoles of NaOH = 58.99 X 0.0372 = 2.1944

Now CH₃COOH and NaOH reacts to give CH₃COONa according to the reaction :

CH₃COOH + NaOH ------> CH₃COONa + H₂O

1 mole of CH₃COOH reacts with 1 mole of NaOH to give 1 mole of CH₃COONa

So 2.1944 millimoles of CH₃COOH will react with 2.1944 millimoles of NaOH to give 2.1944 millimoles of CH₃COONa

So all the acid (CH₃COOH) and base (NaOH) has been converted into salt (CH₃COONa) so there is no acid or base left.

Now molarity of CH₃COONa = number of millimoles of CH₃COONa/total volume in ml = 2.1944/(58.99 + 42.2) = 2.1944/101.19 = 0.02169 M

So using the hydrolysis equation :

pH = 1/2 [ pKw + pKa + log c ]

Ka for acetic acid = 1.75 X 10⁻⁵

so pKa = -log (1.75 X 10⁻⁵) = 4.74

Kw = 10⁻¹⁴

so pKw = -log 10⁻¹⁴ = 14

c = 0.02169

so log c = log 0.02169 = -1.66

putting the values....

pH = 1/2 [14 + 4.74 - 1.66 ]

pH = 1/2 [ 17.08] = 8.54

6 0

2 years ago

Read 2 more answers

1. Calculate the [H] in a solution that has a pH of 9.88.

Olenka [21]

The answer to the question is D.

5 0

2 years ago

Read 2 more answers