Mars is 139.58 million miles away from the sun. mars is red because its soil has iron oxide (rust particles) in it.
The answer would be A, as B refers to conduction and C and D refer to radiation. Convection is the transfer of different temperature currents, i.e, A
Answer:
A.model the reflection of a light wave
The Wave Model of Light Toolkit provides teachers with standards-based resources for designing lesson plans and units that pertain to such topics as the light's wavelike behaviors, wave-particle duality, light-wave interference, and light polarization
B. .model the absorption of a light wave
The simplest model is the Drude/Lorentz model, where the light wave makes charged particle oscillate while the particle is also being damped by a force of friction (damping force)
A mirror provides the foremost common model for reflective light wave reflection and generally consists of a glass sheet with a gold coating wherever the many reflections happen. Reflection is increased in metals by suppression of wave propagation on the far side their skin depths
C.model the transmimssion of a light wave
The Wave Model describes how light propagates in the same way as we model ocean waves moving through the water. By thinking of light as an oscillating wave, we can account for properties of light such as its wavelength and frequency. By including wavelength information, the Wave Model can be used to explain colors.
Explanation:
Answer:
The work done by the wind as the boat moves 130 ft is (rounded) W= 31,550 ft-lb.
Explanation:
F= 300 lb < -54º
Fsouth= 300 lb * cos(36º)
Fsouth= 242.7 lb
d= 130 ft
W= F*d
W= 31551 ft-lb
Answer:
619.8 N
Explanation:
The tension in the string provides the centripetal force that keeps the rock in circular motion, so we can write:
where
T is the tension
m is the mass of the rock
v is the speed
r is the radius of the circular path
At the beginning,
T = 50.4 N
v = 21.1 m/s
r = 2.51 m
So we can use the equation to find the mass of the rock:
Later, the radius of the string is decreased to
r' = 1.22 m
While the speed is increased to
v' = 51.6 m/s
Substituting these new data into the equation, we find the tension at which the string breaks:
