10. What is the acceleration due to gravity at a location

What is the difference between beta plus and minus

Minchanka [31]

Beta decay is very complex phenomena in natural radioactive decay. There are 3 types of Beta decay.

B+ decay (Beta plus or Beta positive or positron decay):

is the conversion of a proton into a neutron plus a positron and an electron neutrino.

B- decay (Beta negative or Beta nought):

is the conversion of a neutron into a proton plus an electron and a electron antineutrino.

Note: a positron is the a positive electron or the antiparticle of the electron.

Hope it helps

7 0

2 years ago

The velocity of a particle moving along the x-axis varies with time according to v(t) = A + Bt−1 , where A = 2 m/s, B = 0.25 m,

kondaur [170]

Answer:

$a= -2\ m/s^2$

$a=-12.5\ m/s^2$

x=2.17 m

x=8.4 m

Explanation:

Given that

$v=A+Bt^{-1}$

$v=2+0.25t^{-1}$

To find acceleration :

we know that

$a=\dfrac{dv}{dt}$

$\dfrac{dv}{dt}=0-0.5t^{-2}$

$a=-0.5t^{-2}$

Acceleration at t= 2 s

$a=-0.5\times 2^{-2}$

$a= -2\ m/s^2$

Acceleration at t= 5 s

$a=-0.5\times 5^{-2}$

$a=-12.5\ m/s^2$

We know that

$v=\dfrac{dx}{dt}$

$dx=\left(2+\dfrac{1}{4t}\right)dt$

Position at t= 2 s:

$\int_{0}^{x}dx=\int_{1}^{2} \left(2+0.25\dfrac{1}{t}\right)dt$

$x=\left [2t+0.25\ lnt \right ]_{1}^{2}$

x=2+0.25 ln2

x=2.17 m

Position at t= 5 s:

$\int_{0}^{x}dx=\int_{1}^{5} \left(2+0.25\dfrac{1}{t}\right)dt$

$x=\left [2t+0.25\ lnt \right ]_{1}^{5}$

x=8+0.25 ln5

x=8.4 m

4 0

2 years ago

1 jWhat is the correct unit for temperature?

Nadya [2.5K]

Answer:

Answer: Kelvin ________________

8 0

2 years ago

A wire with a resistance of 20 Ω (Ohm's) is connected to a 12-V battery. What is the current flowing through the wire? (Blank) A

pishuonlain [190]

For this particular problem, we use Ohm's Law. This law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. Using the equation, we can isolate I or the current to one side and the other terms to the other side. We calculate as follows:

V = IR
I = V/R
I = 12 V / 20 Ω
I = 0.6 amperes

Therefore, the current that is flowing through the wire supplied with 12 V and having a resistance of 20 Ω would be 0.6 amperes.

8 0

2 years ago

Read 2 more answers

5. For the following pairs of masses, which one has the largest gravitational attraction between masses? Which one has the small

sasho [114]

Answer:

MOST : E LEAST : D

Explanation:

Grav attraction = G m1 m1 / r^2

G and 'r' are the same for all of the pictures, so the one picture with the biggest mass has the MOST attraction and the one with the least mass has the least attraction.

8 0

1 year ago