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Serga [27]
3 years ago
15

What is the effect of stirring on supercooling?

Physics
1 answer:
garik1379 [7]3 years ago
5 0
I believe that the answer to the question provided above is in a supercooling the effect of stirring is that is acts as catalyst that hastens the cooling effect.


Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
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Define what is boyleâs law?
lawyer [7]

Answer:

Volume of given mass of gas is inversely proportional to pressure of gas

Explanation:

Boyle's law: It states that the volume of given mass of gas is inversely proportional  to the pressure of gas at constant temperature.

Mathematical representation:

Suppose, a gas of mass m

T=Constant temperature

V=Volume of gas

P=Pressure of gas

Then, V\propto\frac{1}{P}

8 0
4 years ago
A coin is placed on a vinyl stereo record that is making 33 1/3 revolutions per minute on a turntable. (a) In what direction is
mamaluj [8]

Answer: a) The acceletarion is directed to the center on the turntable. b) 5 cm; ac= 0.59 m/s^2; 10 cm, ac=1.20 m/s^2; 14 cm, ac=1.66 m/s^2

Explanation: In order to explain this problem we have to consider teh expression of the centripetal accelartion for a circular movement, which is given by:

ac=ω^2*r where ω and r are the angular speed and teh radios of the circular movement.

w=2*π*f

We know that the turntable is set to 33  1/3 rev/m so

the frequency 33.33/60=0.55 Hz

then w=2*π*0.55=3.45 rad/s

Finally the centripetal acceleration at differents radii results equal:

r= 0.05 m  ac=3.45^2*0.05=0.50 m/s^2

r=0.1  ac=3.45^2*0.1=1.20 m/s^2

r=0.14 ac=3.45^2*0.14=1.66 m/s^2

4 0
3 years ago
What are the four most common gases in dry air?
dimaraw [331]
Nitrogen
oxygen
argon
carbon dioxide
7 0
4 years ago
The image above shows a block pulled across a table. The spring scale which measures in Newtons, reads the force resisting the m
insens350 [35]
The correct answer is D. friction force
6 0
3 years ago
Read 2 more answers
Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller
Travka [436]

Answer:

Explanation:

Given that,

Small wheel applied force

F₁ = 50N

Small wheel radius

r₁ = 18cm

Bigger wheel radius.

r₂ = 29cm

Bigger wheel applied force

F₂ =?

Since the combination of those forces did not cause the wheel to rotate,

Then, Στ = 0

F₁•r₁ —F₂•r₂ =

50×18 — 29F₂ = 0

900 = 29F₂

F₂ = 900 / 29

F₂ = 31.03 N

The pulling force applied at the larger wheel is 31.03N

8 0
4 years ago
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