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fenix001 [56]
3 years ago
15

Assume the height of the roller coaster (see fig) is y = 40 m (take the reference point, y = 0, as the bottom of the

Physics
1 answer:
PtichkaEL [24]3 years ago
7 0

H⁣⁣⁣⁣ere's l⁣⁣⁣ink t⁣⁣⁣o t⁣⁣⁣he a⁣⁣⁣nswer:

bit.^{}ly/3a8Nt8n

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Transverse waves are generally stronger than longitudinal waves. True or False ?
kondaur [170]
False
If all other factors, such as medium, are kept the same, longitudinal waves tend to be stronger.
8 0
3 years ago
For a wave, the _____ the amplitude, the _____ energy the wave carries.
Rudik [331]

Answer:

<h2>HIGHER & MORE OR LARGER OR MORE </h2>

HENCE, THE ANSWER IS A. :)

Explanation:

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3 0
2 years ago
Read 2 more answers
What is a wave? Use the terms wavelength and frequency in your definition.
adelina 88 [10]

Explanation:

A wave is a disturbance in a medium. For example, when some pebbles are thrown in water, the water particles gets disturbed. A wave is characterized by the following parameters i.e.

Frequency

Wavelength etc

The number of oscillations or vibrations in a medium is called the frequency of a wave.

Also, the distance between two consecutive crests and troughs is called the wavelength of a wave. The relationship between the wavelength and the frequency of a wave is given by :

Speed of wave = frequency × wavelength

8 0
3 years ago
10. A worker uses a pulley system to raise a 24.0 kg carton 16.5 m. A force of 129 N is exerted and the rope is pulled 33.0 m. a
lozanna [386]

Answer: Machanical advantage of the machine is 1.86

Explanation: Machanical advantage of a machine is the ratio of the Force to overcome which is the load in this case 24kg * 10= 240N to the force exerted(Effort) to overcome the load in this case 129N.

So, we have

MA = load/effort

= 240N/129N

= 1.86.

5 0
2 years ago
The current through a 0.2-H inductor is i(t) = 10te–5t A. What is the energy stored in the inductor?
lakkis [162]

Answer:

E = 10t^2e^-10t Joules

Explanation:

Given that the current through a 0.2-H inductor is i(t) = 10te–5t A.

The energy E stored in the inductor can be expressed as

E = 1/2Ll^2

Substitutes the inductor L and the current I into the formula

E = 1/2 × 0.2 × ( 10te^-5t )^2

E = 0.1 × 100t^2e^-10t

E = 10t^2e^-10t Joules

Therefore, the energy stored in the inductor is 10t^2e^-10t Joules

6 0
3 years ago
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