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Jet001 [13]
3 years ago
12

when a substance goes through a chemical change, it forms a new substance that has different physical and chemical properties

Chemistry
1 answer:
Westkost [7]3 years ago
5 0
True. The thing about chemical changes is that it is not easily reversible and new substances having different chemical properties are formed. For example; burning of wood to ashes.
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PLEASE HELP !!!!!!!
Romashka-Z-Leto [24]

Answer:

b

Explanation:

3 0
3 years ago
How do i solve number 36?
tresset_1 [31]
To cut this short and for your understanding, ionic bond is formed between metals (mostly right column in periodic table). Covalent bond is formed between non-metals (mostly left column in periodic table). So polar covalent is also a covalent bond but it is polar, which means the shape of molecules are not symmetrical hence maybe an atom in a molecule has most of the electron attracted to it causing itself to be partial negative (since electron are negatively charged) and the other atom has its electron being attracted by others became partial positive. Polar covalent can also be when H atom is binding either to F, O or N (also known as hydrogen bond).
6 0
3 years ago
Need help with this can some please help
vekshin1
I believe you would just put a 2 in front of NH3 and keep the other ones as 1
7 0
3 years ago
How do you solve this ??
kotegsom [21]
Answer : Option A) 2.00 eV

Explanation : The conversion of J to eV is done with the following formula;

E_{eV} = E_{J} X (6.241 X 10^{18})

Here, we have the value of particle in terms of Joules which is 3.2 X 10^{-19}

So, on substituting we get,
E_{eV} = 3.2 X 10^{-19}  X  (6.241 X 10^{18} )


E_{eV} = 1.99 eV so, it can be rounded off to 2.00 eV.
3 0
3 years ago
Type the correct answer in each box.
Arturiano [62]

Answer:

5SiO2 + 2CaC2 = 5Si + 2CaO + 4CO2

Explanation:

balancing equations is a lot of trial and error. My strategy to approaching this equation was to get the O's balanced. After trying several combonations I found that I needed 10 O's on each side of the equation for the other elements to match up. After I balanced the O's, I balanced my C's to 4 on each side. Then I balanced my Ca's to have 2 on each side. And last but not least I balanced my Si to have 5 on each side.

8 0
3 years ago
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