Answer:
The factor of increasing reaction rate is 1,85x10¹².
Explanation:
Using arrhenius formula:
Where k is rate constant; A is frecuency factor; Eₐ is activation energy; R is gas constant (0,008134 kJ/molK); T is temperature 25°C = 298,15K
Thus, replacing for an activation energy of 125 kJ/mol assuming A as 1:
k = 1,25x10⁻²²
When activation energy is 55kJ/mol:
k = 2,31x10⁻¹⁰
Thus, the factor of increasing reaction rate is:
2,31x10⁻¹⁰/1,25x10⁻²² =<em> 1,85x10¹²</em>
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I hope it helps!
The average atomic mass of your mixture is 1.03 u
.
The average atomic mass of H is the weighted average of the atomic masses of its isotopes.
We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).
Thus,
0.99 × 1.01 u = 0.998 u
0.002 × 2.01 u = 0.004 u
0.008 × 3.02 u = <u>0.024 u</u>
TOTAL = 1.03 u
Q. How many molecules of H2O can be produced from reactants in container below?
A. 3 molecule of molecules H2O will be produced from reactants in container.
<em><u>Explanation</u><u>:</u></em>
There are seven molecules of H2 and three molecule of O2 are there in the container Q, 6 molecules of H2 will react with 3 molecules of O2 to produce 3 molecules of H2O. One molecule of Hydrogen will not take part in reaction and will be present in container Q after then reaction, and the mass in overall reaction is conserved!
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Answer:
Partial pressure of 
in the gas was 733 torr and mass of 
in the sample was 2.12 g.
Explanation:
a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of )
Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.
So, partial pressure of = (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr
b) Lets assume that behaves ideally. Hence-
PV=nRT
where P is pressure of , V is volume of , n is number of moles of , R is gas constant and T is temperature in kelvin
here P = 733 torr = 
= 0.9646 atm
V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K
So, 
= 
= 0.0259 moles
As 3 moles of are produced from 2 moles of therefore 0.0259 moles of are produced from 
moles or 0.0173 moles of .
Molar mass of = 122.55 g
So mass of in sample = 
= 2.12 g
