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Mashcka [7]
3 years ago
9

2 What does how much, how long and how often have to do with exposure to chemicals?

Physics
1 answer:
tatiyna3 years ago
4 0

Well how much, how long, and how often  

For example how much is like how much a object is left in a small room with chemicals

How long is the time

how often is how much the same cycle is done repeatedly

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Suppose that a constant force is applied to an object with a mass of 12kg, it’s creates an acceleration of 5m/s^2. The accelerat
Klio2033 [76]

Answer:

Mass of second object will be 15 kg

Explanation:

We have given mass of first object = 12 kg

Acceleration a=5m/sec^2

According to second law of motion we know that force F = MA

So force F=12\times 5=60N

As the same force is applied to the second object of acceleration a=4m/Sec^2

So force = ma

60=m\times 4

m = 15 kg

So mass of second object will be 15 kg

5 0
3 years ago
An audi travels at 88 km/hr over a distance of 22 km. calculate.25 the time taken for the audi to travel this distance.
sammy [17]
The Audi covers 88 in one hour.
22 is one quarter of 88, so it takes one quarter of one hour. That's 15 minutes.
Note:. The answer would be the same for any other brand of car, motorcycle, airplane etc.
4 0
4 years ago
Is cracking the eggs a physical change or a chemical change and why
matrenka [14]

Answer:

Cracking of an egg is a physical change since the egg and the stuff inside does not change but the shape or appearance of the shell changes.

Explanation:

Hope it helps

3 0
3 years ago
What overall charge must a compound have
Vanyuwa [196]
The charge? If you mean valance electrons, the answer is 8. All compounds must be equal to that of a noble gas.
4 0
4 years ago
If the reading of a linear scale is 4 mm and no of division of the circular scale is 50, then what will be the diameter of the w
Sliva [168]

Answer:

Diameter of Wire = 4.5 mm

Explanation:

First, we need to find the fractional part of the reading. The fractional part o the reading can be given by the following formula:

Fractional Part = Circular Scale Reading x Least Count

where,

Circular Scale Reading = 50

Least Count = 0.01 mm

Therefore,

Fractional Part = (50)(0.01 mm)

Fractional Part = 0.5 mm

Now, the diameter of the wire can be given by using the following formula:

Diameter of Wire = Linear Scale Reading + Fractional Part

Diameter of Wire = 4 mm + 0.5 mm

<u>Diameter of Wire = 4.5 mm</u>

8 0
3 years ago
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