Which statement about electromagnetic waves is true?

4. An object moves in a circular path at a constant speed. Compare the direction of the object’s velocity and acceleration vecto

Vikentia [17]

Answer:

Option C

The vectors are perpendicular

Explanation:

Acceleration will be directed towards the center for uniform circular motion. Consequently, velocity of the object increases hence acceleration. The direction of velocity is tangent to its circular motion, therefore, tangential velocity vector is perpendicular to centripetal acceleration vector. Therefore, comparing the direction of the object, the vectors are perpendicular to each other.

4 0

3 years ago

Find the horizontal component and the vertical component

aleksandr82 [10.1K]

Answer:

v=3.66,h-3.66

Explanation:

vertical = 10sin60 - 10sin 30

horizontal =10cos60 + 10cos 30

v = 10×0.8660-10×0.5

h = 10×0.5 + 10 × 0.8660

v=8.660-5.0 = 3.66

h= 5.0-8.660 = -3.66

8 0

3 years ago

A sled and its rider are moving at a speed of 4.0 m/s along a horizontal stretch of snow. The snow exerts a kinetic frictional f

ehidna [41]

Answer:

The acceleration of the sled is "0.49 m/s²". A further explanation is given below.

Explanation:

The given values are,

Speed,

V = 4.0 m/s

Coefficient of kinetic friction,

μ = 0.05

As we know,

⇒ $F \mu=\mu mg$

and,

⇒ $a = \mu g$

On substituting the given values, we get

⇒ $=0.0 5\times 9.8$

⇒ $=0.49 \ m/s^2$

5 0

3 years ago

Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 48.

galina1969 [7]

Given:

The force of attraction is F = 48.1 N

The separation between the charges is

$\begin{gathered} r=\text{ 60.9 cm} \\ =\text{ 60.9}\times10^{-2}\text{ m} \end{gathered}$

Also, the magnitude of charge q1 = q2 = q.

To find the magnitude of charge.

Explanation:

The magnitude of charge can be calculated by the formula

$\begin{gathered} F=\frac{k(2q)}{r^2} \\ q=\frac{Fr^2}{2k} \end{gathered}$

Here, k is the Coulomb's constant whose value is

$k\text{ = 9}\times10^9\text{ N m}^2\text{ /C}^2$

On substituting the values, the magnitude of charge will be

$\begin{gathered} q=\frac{48.1\times(60.9^\times10^{-2})^2}{2\times9\times10^{^9}} \\ =9.91\times10^{-10}\text{ C} \\ =9.91\times10^{-4}\text{ }\mu C \end{gathered}$

Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.

6 0

2 years ago

Suppose there are two identical gas cylinders. One contains the monatomic gas krypton (Kr), and the other contains an equal mass

tensa zangetsu [6.8K]

Answer:

Explanation:

Let equal mass of Ne and Kr be m gm

no of moles of Ne and Kr will be m / 20 and m / 84 ( atomic weight of Ne and Kr is 20 and 84 )

Let the pressure and volume of both the gases be P and V respectively .

The temperature of Ne be T₁ and temperature of Kr be T₂.

For Ne

PV = (m / 20) x R T₁

For Kr

PV = (m / 84) x R T₂

T₁ / T₂ = 84 / 20

We know that

average KE of an atom of mono atomic gas = 3 / 2 x k T

k is boltzmann constant and T is temperature .

KEKr/KENe = T₂ / T₁

= 20 / 84

4 0

3 years ago