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Molodets [167]
3 years ago
14

what is the solution to the equation fraction 3 over 5 n minus fraction 4 over 5 equals fraction 1 over 5 n? n = −1 n = 2 n = fr

action 5 over 3 n = fraction 5 over 2
Mathematics
2 answers:
Norma-Jean [14]3 years ago
4 0
3/5n - 4/5 = 1/5n....multiply everything by 5 to get rid of the fractions
3n - 4 = n
-4 = n - 3n
-4 = -2n
-4/-2 = n
2 = n <==
sdas [7]3 years ago
3 0
\frac{3}{5}n- \frac{4}{5}  = \frac{1}{5}n
Putting like terms together;
\frac{3}{5} n- \frac{1}{5}n= \frac{4}{5}
\frac{2}{5} n= \frac{4}{5}
n=\frac{4}{5} * \frac{5}{2}
n=2

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3 years ago
Anyone please help me pleaseeee
lora16 [44]

R = { (x,y): 3x-y=0 }

The condition is 3x=y so that's not going to be any of these things.

R is reflexive if (x,x)∈R for all x.   Let's check.

3x - y = 3x - x = 2x ≠ 0  necessarily.   NOT REFLEXIVE

R is symmetric if (x,y)∈R → (y,x)∈R.   Let's check.

(x,y)∈R  so

3x-y = 0

y  = 3x

Is  (y,x)∈R.  That would be true if 3y-x=0

3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC

R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R.   Let's check.

3x-y = 0  so y=3x

3y-z = 0 so z=3y = 9x

3x - z = 3x - 9x = -6x ≠ 0 necessarily   NOT TRANSITIVE

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Answer:

m = 3

Step-by-step explanation:

\frac{4}{3} m = 4 \\ divide \: both \: sides \: by \:  \frac{4}{3}  \\  \\ m = 3

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X = 1.5 if that is your question

Step-by-step explanation:

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