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Afina-wow [57]
4 years ago
14

If you want to stop the current flow through Device 3 in the circuit shown above, which one of the following single switches sho

uld you open?
A. Switch S4
B. Switch S3
C. Switch S2
D. Switch S5
Physics
2 answers:
Arturiano [62]4 years ago
7 0
Thats a hard one, From The looks of it, it looks like B, Because it would leave a gap in the flow for a small amount of time
Firdavs [7]4 years ago
6 0
Hello there.

<span>If you want to stop the current flow through Device 3 in the circuit shown above, which one of the following single switches should you open?

</span><span>B. Switch S3
</span>
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A hot-air balloon with a mass of 400 kilograms moves across the sky with 3,200 joules of kinetic energy. The velocity of the bal
kotegsom [21]

Answer:

4 m/s

Explanation:

KE =

Velocity of balloon will be 4 m/s.

!! Hope It Helps !!

4 0
4 years ago
Two 5.0-g aluminum foil balls hang from 1.0-m-long threads that are suspended from the same point at the top. The charge on each
Allisa [31]

Answer: F=0.075N

Explanation:

T*cos(θ) = mg=0.005X9.8

T*cos(θ)=0.049N

T = 0.049/cosθ

F = k*q1*q2 / r2

F = 8.9875 * 10^9 * q1*q2 / r^2 q1

F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2

F=0.2246875/r^2

r= 2Lsinθ = 2 x 1 x sinθ =2sinθ

Kindly check the attached for further solution

5 0
3 years ago
Calculate the acceleration if you push with a 20-N horizontal force on a 2-kg block on a horizontal friction-free air table
Afina-wow [57]
Acceleration = force / mass = 20 / 2 = 10 m/s^2
3 0
3 years ago
Does anyone understand This question if you do can you tell me the answer
leonid [27]

Answer:

50N increasing

Explanation:

it looks like we want the net force. this is the sum of all forces acting on the object. here the problem is extremely simplified and we are even given the values of force. this looks like the rocket is producing an upward force of 160 newtons. it also looks like maybe weight (gravity) and drag (air resistance) are producing downward force against the rocket. we can say those would be subtracting from the amount of upwards force. so 160-40-70=50N. since the force is positive that means we will still have a magnitude of force vector that points upward and so we will increase.

6 0
3 years ago
In a container of negligible mass, 0.400 kg of ice at an initial temperature of -29.0 ∘C is mixed with a mass m of water that ha
Pie

Answer:

1 kg

Explanation:

The container has negligible mass and no heat is loss to the surrounding.

Mass of ice = 0.4kg, initial temperature of ice = -29oC, final temperature of the mixture = 26oC, mass of water (m2) = ?kg, initial temperature of water = 80oC, c ( specific heat capacity of water ) = 4200J/kg.K, Lf = heat of fusion of water = 3.36 × 10^5 J/kg

Using the formula:

Quantity of heat gain by ice = Quantity of heat loss by water

Quantity of heat gain by ice = mass of ice × heat of fusion of ice + mass of water × specific heat capacity of water = (0.4 × 3.36 × 10^ 5) + (0.4 × 4200 × (26- (-29) = 13.44 × 10^4 + 9.24 × 10^ 4 = 22.68 × 10^4 J

Quantity of heat loss by water = m2cΔT

Quantity of heat loss by water = m2 ×4200× (80 - 26) = m(226800)

since heat gain = heat loss

22.68 × 10^4 = 226800 m2

divide both side by 226800

226800 / 226800 = m2

m2 = 1 kg

5 0
3 years ago
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