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Leto [7]
3 years ago
6

Calculate the acceleration if you push with a 20-N horizontal force on a 2-kg block on a horizontal friction-free air table

Physics
1 answer:
Afina-wow [57]3 years ago
3 0
Acceleration = force / mass = 20 / 2 = 10 m/s^2
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Calculate the force of friction that keeps an 80-kg person sitting on the edge of a horizontal rotating platform when the person
Lilit [14]

Answer:

360N

Explanation:

The frictional force = centripetal force = mass * centripetal acceleration = ma

Since centripetal acceleration = V^2/ r

Frictional force = mv^2 / r

Substitute the values of m = 80kg, radius = 2m and tangential speed = 3m/s

Frictional force = 80 * (3)^2/ 2 = 360N

8 0
3 years ago
A 4-kilogram ball moving at 8 m/sec to the right collides with a 1-kilogram ball at rest. After the collision,
elena-14-01-66 [18.8K]
Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s
4 0
4 years ago
A solar panel is used to collect energy from the sun and change it into other forms of energy. The picture below shows some sola
irakobra [83]
C I’m pretty sure!!!!!
4 0
3 years ago
What is a catchy slogan to help people remember the difference between weathering and erosin
GaryK [48]
These are more of ideas to help your brain invent something less chessy...
Erosion is like corrosion, with no acid.
Erosion happens 'cuz the surface get frozen and beaten by the ocean. (they kinda rhyme) :)
Erosion is the transportation of, the deportation... 
~OR~
I cant think of anything for weathering but i got something good, but its still cheesy/ ):

Erosions' got the grooves and so it moves. But weathering breakdown and changes so its molecules changes.
I'm sorry these kinda suck...
5 0
3 years ago
a 230 kg roller coaster reaches the top of the steepest hill with a speed of 6.2 km/h. It then descends the hill, which is at an
igor_vitrenko [27]

Answer: 81.619 kJ

Explanation:

Given

Mass of roller coaster is m=230\ kg

It reaches the steepest hill with speed of u=6.2\ km/h\ or \ 1.72\ m/s

Hill to bottom is 51 m long with inclination of 45^{\circ}

Height of the hill is h=51\sin 45^{\circ}=36.06\ m

Conserving energy to get kinetic energy at bottom

Energy at top=Energy at bottom

\Rightarrow K_t+U_t=K_b+U_b\\\Rightarrow \dfrac{1}{2}mu^2+mgh=K_b+0\\\\\Rightarrow K_b=0.5\times 230\times 1.72^2+230\times 9.8\times 36.06\\\Rightarrow K_b=340.216+81,279.24\\\Rightarrow K_b=81,619.456\ J\\\Rightarrow K_b=81.619\ kJ

8 0
3 years ago
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