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Leto [7]
3 years ago
6

Calculate the acceleration if you push with a 20-N horizontal force on a 2-kg block on a horizontal friction-free air table

Physics
1 answer:
Afina-wow [57]3 years ago
3 0
Acceleration = force / mass = 20 / 2 = 10 m/s^2
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According to information found in an old hydraulics book, the energy loss per unit weight of fluid flowing through a nozzle conn
suter [353]

This question is incomplete, the complete question is;

According to information found in an old hydraulics book, the energy loss per unit weight of fluid flowing through a nozzle connected to a hose can be estimated by the formula; h= (0.04 to 0.09)(D/d)⁴V²/2g

where h is the energy loss per unit weight, D the hose diameter, d the nozzle tip diameter, V the fluid velocity in the hose, and g the acceleration of gravity.

Do you think this equation is valid in any system of units

Answer:

YES, the equation is a general equation that is valid in any system of units

Explanation:

Given the data in the question;

h = (0.04 to 0.09)(D/d)⁴ × \frac{V^{2} }{2g}

so

[ N.m/N ] = (0.04 to 0.09) ( m/m)² × (m²/s²)1/2 × (s²/m)

[ N.L/N ] = (0.04 to 0.09) ( L⁴/L⁴) × (L²/T²)1/2 × (T²/L)

∴ [ L ] = (0.04 to 0.09) [L]

So as each term in the equation must have the same dimensions, the constant term (0.04 to 0.09) must be without dimension.

Therefore, YES, the equation is a general equation that is valid in any system of units

5 0
3 years ago
What height would cause an object to have no gravitational potential energy
OverLord2011 [107]
The height is zero.
That means whatever place is your reference for height measurement,
the object is lying right there at that height.
5 0
3 years ago
Would lifting a 1 kg block 1 meter off the ground be work? Yes or No
JulsSmile [24]

Answer:

NO

Explanation:

8 0
3 years ago
Describe an example of an assignment that could be used in science, technology, engineering, or mathematics that would allow a s
Mashutka [201]

Answer:

A notebook because they can take notes of what they have learned

Explanation:

4 0
3 years ago
A wood pipe having an inner diameter of 3 ft. is bound together using steel hoops having a cross sectional area of 0.2 in.2 The
WINSTONCH [101]

Answer:

31.67 in

Explanation:

Given:

Diameter of the pipe, D = 3ft = 36 in

cross-sectional area of the steel = 0.2 in²

Note: Refer to the figure attached

From the free body diagram represented in the figure, we have

ΣFx = 0

or

pressure × projected area = 2 × Force in steel

Now, the projected area = spacing (s) × diameter of the wood pipe

force in steel = stress in steel (σ) × cross-sectional area of the steel

on substituting the values we get

4 ksi × (s × 36 in) = 2 × σ × 0.2 in²

also, allowable hoop stress = 11.4 ksi

thus,

σ = 11.4 ksi = 11.4 × 10³ psi

therefore, we have

4 psi × (s × 36 in) = 2 × 11.4 × 10³ psi × 0.2 in²

thus,

s = 31.67 in

hence the maximum spacing is 31.67 in

3 0
4 years ago
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