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Leto [7]
3 years ago
6

Calculate the acceleration if you push with a 20-N horizontal force on a 2-kg block on a horizontal friction-free air table

Physics
1 answer:
Afina-wow [57]3 years ago
3 0
Acceleration = force / mass = 20 / 2 = 10 m/s^2
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A taxi starts from Monument Circle and travels 5 kilometers to the east for 5 minutes. Then it travels 10 kilometers to the sout
katovenus [111]

The correct sentence is:

The taxi is moving with reference to  A) Monument circle. For each leg of the trip, the taxi’s  A) Average speed stays the same, but its  B) Average velocity  changes.

In fact, speed it is only the ratio between the distance traveled and the time taken - so it does not take into account the direction of motion. The speed in the first leg is

v=\frac{5 km}{5 min}=1 km/min

while the speed in the second leg is

v=\frac{10 km}{10 min}=1 km/min

so the speed stays the same.

However, the velocity also takes into account the direction of motion: in the first leg, the direction is east, while in the second leg, the direction is south, therefore the average velocity has changed, since the direction has changed.

4 0
3 years ago
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A point charge q1 = 3.0 µC is at the origin and a point charge q2 = 6.0 µC is on the x axis at x = 10 m.
UkoKoshka [18]

Answer:

a) 1.6 mN  b) -1.6 mN  c) -1.6 mN  d) 1.6 mN

Explanation:

The electrostatic force between 2 point charges, obeys the Coulomb's Law, that can be expressed as follows:

F₁₂ = k*q₁*q₂/(r₁₂)² (in magnitude)

The direction of the force, is along the  line that joins the  charges (along the x axis) and as q₁ and q₂ are of the same sign, aims away from both charges.

a) So, for the force on q₂, we have:

F₁₂ = 9*18*10⁻⁵ N = 1.6 mN (positive as it is aiming in the positive x direction)

b) The force on q1, according to Newton's 3rd Law, is just equal and opposite to the one on q2:

F₂₁ = (-9*18*10⁻⁵) N = -1.6 mN (towards the negative x direction, away from q1)

c) If q₂ were -6.0 μC, the force will be the same in magnitude, but as now both charges have different signs, they wil attract each other, so the direction of the forces will be exactly the opposite to the first case:

F₁₂ = -1.6 mN (going towards the origin, where q₁ is located)

F₂₁ =  1.6 mN (going in the positive x direction, towards q₂)

6 0
3 years ago
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A straight, cylindrical wire lying along the x axis has a length L and a diameter d . It is made of a material described by Ohm'
Zepler [3.9K]

The magnitude and direction of the electric field in the wire are mathematically given as

L &=[(v / L) v / m] \hat{i}

<h3>What is the magnitude and direction of the electric field in the wire?</h3>

Generally, the equation for is  mathematically given as

A cylindrical wire that is straight and parallel to the x-axis has the following dimensions: length L, diameter d, resistivity p, diameter d, potential v, and z length. combining elements from both sides  

E d x=\int d v.

\begin{aligned}&-E \int_0^L d x=\int_v^0 d v \\\therefore E \cdot L &=v \\L &=[(v / L) v / m] \hat{i}\end{aligned}

In conclusion, the magnitude and direction of the electric field in the wire are given as

L &=[(v / L) v / m]

Read more about electric fields

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7 0
2 years ago
Which equation correctly represents the gravitational potential energy of a system?​
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E = mass x gravity x height
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3 years ago
Choose all of the true statements regarding the relationship between voltage, resistance, and current. Current is measured in am
AveGali [126]

-- <u><em>Current is measured in amps.</em></u>  (You can use any symbol you want to represent current, but the most common one is " I ", not "Δ".)

-- <u><em>The relationship between current, voltage, and resistance is mathematically defined by Ohm's Law. </em></u>

-- <u><em>Current is the flow of electrons through a circuit.</em></u>

-- (Ohm's Law is NOT mathematically represented by the equation V=I/R.)  <u><em>It should be V = I · R</em></u> .  

(When solving for Resistance in a circuit and both voltage and current are known values, the equation I =V*R is not true, and not the way to solve it.)  <u><em>If the resistance is what you're looking for, then the equation to use is  </em></u><u><em>R = V / I</em></u><u><em> .  </em></u>

<em>-- </em><u><em>If the voltage in a circuit is increased, the current will also increase.</em></u>

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3 years ago
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