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3 years ago

6. Which of the following is an example of a vector quantity?

Physics

1 answer:

ivann1987 [24]3 years ago

5 0

Answer:

can I have a picture or like options

Explanation:

please , if you send them I'll edit answer

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What is the source of geothermal energy? User: What is the source of geothermal energy?

bazaltina [42]

The answer is; C

In particular points in the earth’s surface, underground water is naturally heated to steam that can be harness for geothermal energy. The steam that ejects from the ground with high kinetic energy can be used to turn turbines that generate electricity. The underground water is usually heated by the hot rocks beneath that are subjected to the immense heat of magma or the enormous pressure of overlying crust.

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3 years ago

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NEED HELP PLEASE!!!!!! 19 POINTS!!

podryga [215]

When the kinetic energy is transformed into another for of energy during the collision or impact

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3 years ago

A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4

bija089 [108]

Answer:

w = 0.55 rad / s

Explanation:

For this exercise let's use the conservation of angular momentum, let's write the moment in two moments

Initial

L₀ = r p + 0

L₀ = r mv

The first term is the angular momentum of the mass

Final

Lf = (I + m r²) w

Where I is the moment of inertia of the stool and the other term is the moment of inertia of the mass

L₀ = Lf

r mv = (I + m r²) w

w = m r v / (I + m r²)

Let's calculate

w = 2.0 0.45 3.0 / (4.5 + 2.0 0.45²)

w = 2.7 / 4.9

w = 0.55 rad / s

4 0

4 years ago

Two ions with masses of 5.29×10−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic field is

riadik2000 [5.3K]

Answer:

0.132 m

Explanation:

$m$ = mass of the ion = 5.29 x 10⁻²⁷ kg

$q$ = magnitude of charge on singly charged ion = 1.6 x 10⁻¹⁹ C

$r$ = radius of circular path followed by singly charged ion

$v$ = speed of the ion = 1.13 x 10⁶ m/s

$B$ = magnitude of the magnetic field = 0.283 T

Radius of the circular path is given as

$r = \frac{mv}{qB}$

$r = \frac{(5.29\times 10^{-27})(1.13\times 10^{6})}{(1.6\times 10^{-19})(0.283)}$

$r$ = 0.132 m

6 0

3 years ago

A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00 m above the ground. At th

Elis [28]

Answer:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.

Explanation:

The motions of the two water ballons are ruled by the kinematic equations:

$y=y_0+V_0t-gt^2/2$

We are only interested in the vertical motion, so that equation is all what you need.

1. Water ballon is thrown horizontally at sped 2.00 m/s.

The time the ballon takes to hit the ground is independent of the horizontal speed.

Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.

Then:

$y=y_0+V_0t-gt^2/2\\ \\ 0=6.00m-9.8\frac{m}{s^2} t^2/2\\ \\ t=\sqrt{2\times6.00m/9.8\frac{m}{s^2}}\\\\ t=1.11s$

2. Water ballon thrown straight down at 2.00 m/s

Now the initial vertical speed is 2.00 m/s down. So, the equation is:

$0=6.00m-2.00\frac{m}{s}t-9.8\frac{m}{s^2}t^2/2\\ \\ 4.9t^2+2t-6=0\\ \\ t=0.92s$

To solve the equation you can use the quadratic formula.

$t=\frac{-2+/-\sqrt{2^2-4(4.9)(-6)} }{2(4.9)}\\ \\ t=-1.33\\ \\ t=0.92$

You get two times. One of the times is negative, thus it does not have physical meaning.

3. Conclusion:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

5 0

3 years ago