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Olenka [21]
3 years ago
15

You invest $3,150.00 in a stock plan. The first year, it loses 5% of its value. The second year, it gains 9% of its value. What

is the value of your stocks in the second year compared to your initial investment?
Mathematics
2 answers:
Norma-Jean [14]3 years ago
4 0
First year it loses 5%
3,150×(1−0.05)
=2,992.5
second year gains 9%
2,992.5×(1+0.09)
=3,261.825
Gennadij [26K]3 years ago
3 0

Answer:

111.83 is the answer that is accepted by the quiz.


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Whats the first term of geometric sequence ___ 1,5,25,
zzz [600]

Answer:

0,2

Step-by-step explanation:

the rule of this geometric sequence is: divide 5

we turn the sequence to 25,5,1,_

Like <u>25:5=5;5:5=1;</u><u>1:5=0,2</u>

I hope it'll help you much

Thank you for asking

7 0
3 years ago
A container ship left port last week caring some good weighing a total of 125,890 tons today I stopped in another port to unload
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

You need to be specific.  Did the weight decrease by 60 tons or 60 pounds?  I assume tons, but in math, you can't assume.

This problem seems overly simple, so I am wondering if some information is missing.  With the given information and assuming the decrease was in fact 60 tons, you would have:

125,890 - 60 = 125,830 tons

8 0
3 years ago
Nine less than a number is no more than 8 and is no less than 3
Fittoniya [83]

X<17, if i got it correct

7 0
3 years ago
Read 2 more answers
The x-coordinate of point P is positive, and the y-coordinate of point P is negative. In which quadrant is point P?
Naddika [18.5K]

ANSWER

Quadrant IV

EXPLANATION

The given point have the x-coordinate to be positive and the y-coordinate to be negative.

In general, the point P(x,-y) lies in the fourth quadrant.

The reason is that, this quadrant contains the positive x-axis and the negative y-axis.

See attachment for diagram.

8 0
3 years ago
(01.03. 106, 1.08 HC)
zlopas [31]

Answer:

  A) see attached for a graph. Range: (-∞, 7]

  B) asymptotes: x = 1, y = -2, y = -1

  C) (x → -∞, y → -2), (x → ∞, y → -1)

Step-by-step explanation:

<h3>Part A</h3>

A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:

  \dfrac{-x^2+x+2}{x^2-3x+2}=-\dfrac{(x-2)(x+1)}{(x-2)(x-1)}=-\dfrac{x+1}{x-1}\quad x\ne 2

This has a vertical asymptote at x=1, and a hole at x=2.

The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.

The graph is attached.

The range of the function is (-∞, 7].

__

<h3>Part B</h3>

As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.

The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.

__

<h3>Part C</h3>

The end behavior is defined by the horizontal asymptotes:

  for x → -∞, y → -2

  for x → ∞, y → -1

7 0
2 years ago
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