Answer:
See the attachment
Verification shown in explanation
Explanation:
wc= 1/(RC)
The value of R and C shown in the attachment can be calculated as follows:
R=100 ohms
1000= 1/(100×C)
C= 10 microfarads
Gain= R/√(R²+Xc²)
at f=500, wc= 3142.59 rad/s
Xc= 1/(2πfC)
Xc=31.83
Gain= 100/√(100²+31.83²)
Gain= 0.953
at fc= 100, wc= 628.32 rad/s
Xc= 159.15
gain= 100/√(100²+ 159.15²)
gain= 0.532
As see form calculations that gain at low frequencies is smaller and gain at very high frequencies is near to 1. This means that at high frequencies Vin≈ Vout
Hence this filter allows high frequencies to pass but blocks low frequencies by lowering the gai
Answer:
784.090909mph
Explanation:
1ft/s=0.681818 mph
1150ft/s=0.681818 x 1150=784.090909
Answer:
High speed cutting steel tool are commonly used steel tool for cutting the tool materials. It is basically used in condition when the material looses its hardness and it is a subset of tool steel. It is majorly used in power saw blades.
There are mainly two types of high speed steel cutting tools are:
1) Tungsten type: This type of tool are basically designed for T grades. Tungsten maintains the efficiency and properties in the high temperature. It is denoted by T1.
2) Molybdenum type: This type of tool are designed for M grade and it is widely use in industries. Molybdenum high speed steel are better in certain cases as compared to tungsten type.
Answer:
Answer is. (d) all of the above
Answer:
The electrical power is 96.5 W/m^2
Explanation:
The energy balance is:
Ein-Eout=0
if:
Gsky=oTsky^4
Eb=oTs^4
qc=h(Ts-Tα)
if Gl≈El(l,5800)
lt= 2*5800=11600 um-K, at this value, F=0.941
The hemispherical emissivity is equal to:
lt=2*333=666 K, at this value, F=0
The hemispherical absorptivity is equal to: