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padilas [110]
2 years ago
5

4. What are the basic scientific principles the engineers who designed the digital scales would have needed to understand to des

ign this tool? Choose all that apply. A. Electric currents B. Physical properties of metals C. Influence of gravitational force on objects D. Physical and chemical properties of materials used in building circuits
Engineering
1 answer:
tamaranim1 [39]2 years ago
5 0

Answer:

Electric currents

Physical properties of metals

Influence of gravitational force on objects

Explanation:

The engineer who designed the digital scale must have a good working knowledge of the electric current, and its principle of flow through various materials, and also, factors that can affect its flow through a material (especially metals).

The physical properties of metal would have to be known by the engineer, in order to design the digital scale. The engineer must be able to predict some of the effect of the changes in the physical properties of a metal, and then use this to get some function that he wants from the digital scale, especially the effect of these physical changes on the electrical conducting ability of a metal.

The knowledge of the effect of gravitational force on objects is a must-know for the engineer. The process of scaling here on earth is very much dependent on the gravitational pull on objects downwards to the earth. This knowledge can be used to predict how much deflection this gravity forces will induce on an object towards the earth.

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2 years ago
Errors in the output voltage of an actual integrated circuit operational amplifier can be caused by : Select one:
natta225 [31]

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Option B

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7 0
3 years ago
For a steel alloy it has been determined that a carburizing heat treatment of 15 h duration will raise the carbon concentration
Amiraneli [1.4K]

Answer:

135 hour

Explanation:

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we know that \frac{x_1^2}{Dt}=constant where x is distance and t is time .As the temperature is constant so D will be also constant

So \frac{x_1^2}{t}=constant

then \frac{x_1^2}{t_1}=\frac{x_2^2}{t_2} we have given x_1=2 mm\ ,t_1=15 hour\ ,x_2=6\ mm and we have to find t_2 putting all these value in equation

\frac{2^2}{15}=\frac{6^2}{t_2}

so t_2=135\ hour

5 0
3 years ago
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