Need Answers Quick!!!! What is the purpose of structural components such as frames, bearings, and mounts? A.) Connect two rotati
1 answer:
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Answer:
0.5 kW
Explanation:
The given parameters are;
Volume of tank = 1 m³
Pressure of air entering tank = 1 bar
Temperature of air = 27°C = 300.15 K
Temperature after heating = 477 °C = 750.15 K
V₂ = 1 m³
P₁V₁/T₁ = P₂V₂/T₂
P₁ = P₂
V₁ = T₁×V₂/T₂ = 300.15 * 1 /750.15 = 0.4 m³
For ideal gas, = 5/2×R = 5/2*0.287 = 0.7175 kJ
PV = NKT
N = PV/(KT) = 100000×1/(750.15×1.38×10⁻²³)
N = 9.66×10²⁴
Number of moles of air = 9.66×10²⁴/(6.02×10²³) = 16.05 moles
The average mass of one mole of air = 28.8 g
Therefore, the total mass = 28.8*16.05 = 462.135 g = 0.46 kg
∴ dQ = 0.46*0.7175*(750.15 - 300.15) = 149.211 kJ
The power input required = The rate of heat transfer = 149.211/(60*5)
The power input required = 0.49737 kW ≈ 0.5 kW.
Answer:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
Explanation:
Answer:
a. W = 51,194.54 kJ
b. W = 102,390 kJ
c. W = 153,585 kJ
Explanation:
a. the ground at 15°C.
=20°C = 273 K + 20 = 293 K
=15°C = 273 K + 15 = 288 K
W = 51,194.54 kJ
b. a pond at 10°C.
=10°C = 273 K + 10 = 283 K
W = 102,390 kJ
c. the outside air at 5°C.
=5°C = 273 K + 5 = 278 K
W = 153,585 kJ
Hope this helps!