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ankoles [38]
3 years ago
6

If the moon is new as seen from the earth, what phase would the earth be in as seen by an astronaut on the moon? explain your re

asoning.
Physics
1 answer:
IrinaK [193]3 years ago
8 0
<span>The earth would be fully visible or full, because it is always seen as an opposite phase than what would normally be seen when we look at the moon. For instance, if we see the moon as almost full then from the moon the earth would appear as a slim crescent.</span>
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How do amplitude and frequency affect light energy? help asap !!!!!!
Lubov Fominskaja [6]
So, I’m assuming that we’re treating light as a propagating wave.


Amplitude measures the amount of energy transported by a wave, thus amplitude squared is directly proportional to the light’s energy. The higher the amplitude, the higher the energy.


Energy is also directly proportional to the frequency of a wave, the higher the frequency, the higher the energy.

I took my second answer from the formula below:

E=cf
7 0
3 years ago
Identify the relationship between kinetic energy and gravitational potential energy for the cyclist at each position
sasho [114]

Answer:

follows are the responses to the given question:

Explanation:

The kinetic energy of every object moving.  PK=m \times v^2 any entity lifted against the strength of gravity stores elastic potential of gravity.

PE = height \times mass  \times  g

Its total power of an independent device stays constant underneath the Mass conservation on Energy and it is, the kinetic energy plus potential energy is just like a fixed (KE+PE=Standard). So, if KE improves, it is valid that PE declines.

If the PE is now at least then KE has been at the highest. It is also valid that KE is reduced as PE is increased as well as the maximum PE, the minimum KE.

5 0
3 years ago
What is NOT one of the three primary resources that families have to reach financial goals?
Elodia [21]
What is NOT one of the three primary resources that families have to reach financial goals? It is c) education
8 0
3 years ago
A pitcher delivers a fast ball with a velocity of 43 m/s to the south. the batter hits the ball and gives it a velocity of 51 m/
hoa [83]
Assuming north as positive direction, the initial and final velocities of the ball are:
v_i=-43 m/s (with negative sign since it is due south)
v_f=+51 m/s
the time taken is t=1.0 ms=0.001 s, so the average acceleration of the ball is given by
a= \frac{v_f-v_i}{t}= \frac{51 m/s-(-43 m/s)}{0.001 s}=9.4 \cdot 10^4 m/s^2
And the positive sign tells us the direction of the acceleration is north.
4 0
3 years ago
A 5 meter long ladder leans against a wall. The bottom of the ladder slides away from the wall at the constant rate of 1 3 m/s.
Oksana_A [137]

Answer:9.75 m/s

Explanation:

Given

Length of ladder (L)=5 m

Foot the ladder is moving away with speed of \frac{\mathrm{d} x}{\mathrm{d} t}=13 m/s

From diagram

x^2+y^2=L^2------1

at x=3

y^2=25-9=16

y=4 m

Now differentiating equation 1 w.r.t time

2x\frac{\mathrm{d} x}{\mathrm{d} t}+2y\frac{\mathrm{d} y}{\mathrm{d} t}=0

x\frac{\mathrm{d} x}{\mathrm{d} t}=-y\frac{\mathrm{d} y}{\mathrm{d} t}

3\times 13=-4\times \frac{\mathrm{d} y}{\mathrm{d} t}

\frac{\mathrm{d} y}{\mathrm{d} t}=-\frac{3\times 13}{4}=-9.75 m/s

negative indicates distance is decreasing with time

5 0
3 years ago
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