Answer:
Explanation:
Given
Cross-sectional area of wire
Extension of wire
Extension in a wire is given by
where,
for same force, length and material
Divide (i) and (ii)
Question 2 (1 point)
1 answer:
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Answer:
a.
b.
Explanation:
I have attached an illustration of a solid disk with the respective forces applied, as stated in this question.
Forces applied to the solid disk include:
Other parameters given include:
Mass of solid disk,
and radius of solid disk,
a.) The formula for determining torque (), is
Hence the net torque produced by the two forces is given as a summation of both forces:
b.) The angular acceleration of the disk can be found thus:
using the formula for the Moment of Inertia of a solid disk;
where = Mass of solid disk
and = radius of solid disk
We then relate the torque and angular acceleration () with the formula:
Answer:
a)-1.014x J
b)3.296 x J
Explanation:
For Sphere A:
mass 'Ma'= 47kg
xa= 0
For sphere B:
mass 'Mb'= 110kg
xb=3.4m
a)the gravitational potential energy is given by
= -GMaMb/ d
= - 6.67 x
x 47 x 110/ 3.4 => -1.014x
J
b) at d= 0.8m (3.4-2.6) and =-1.014x
J
The sum of potential and kinetic energies must be conserved as the energy is conserved.
+
=
+
As sphere starts from rest and sphere A is fixed at its place, therefore is zero
=
+
The final potential energy is
= - GMaMb/d
Solving for ' '
=
+ GMaMb/d => -1.014x
+ 6.67 x
x 47 x 110/ 0.8
= 3.296 x
J