Answer:
C. 98 J
Explanation:
The appropriate formula is ...
PE = mgh . . . . . m is mass; below, m is meters
PE = (5 kg)(9.8 m/s^2)(2 m) = 98 kg·m^2/s^2
PE = 98 J
Answer:
The work done by the child as the tricycle travels down the incline is 416.96 J
Explanation:
Given;
initial velocity of the child,
= 1.4 m/s
final velocity of the child,
= 6.5 m/s
initial height of the inclined plane, h = 2.25 m
length of the inclined plane, L = 12.4 m
total mass, m = 48 kg
frictional force,
= 41 N
The work done by the child is calculated as;

Therefore, the work done by the child as the tricycle travels down the incline is 416.96 J
Answer:
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Explanation:
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Answer:
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Explanation:
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