Answer:
The question is incomplete, below is the complete question "A particle moves through an xyz coordinate system while a force acts on it. When the particle has the position vector r with arrow = (2.00 m)i hat − (3.00 m)j + (2.00 m)k, the force is F with arrow = Fxi hat + (7.00 N)j − (5.00 N)k and the corresponding torque about the origin is vector tau = (4 N · m)i hat + (10 N · m)j + (11N · m)k.
Determine Fx."

Explanation:
We asked to determine the "x" component of the applied force. To do this, we need to write out the expression for the torque in the in vector representation.
torque=cross product of force and position . mathematically this can be express as

Where
and the position vector

using the determinant method to expand the cross product in order to determine the torque we have
![\left[\begin{array}{ccc}i&j&k\\2&-3&2\\ F_{x} &7&-5\end{array}\right]\\\\](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C2%26-3%262%5C%5C%20F_%7Bx%7D%20%267%26-5%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C)
by expanding we arrive at

since we have determine the vector value of the toque, we now compare with the torque value given in the question

if we directly compare the j coordinate we have

Answer:
Modeling tool or Align tool. it depends what type of sandbox platform you use
Explanation:
1
Answer:
A.2.95 m
B.7
Explanation:
We are given that
Diffraction grating=600 lines/mm
d=
Wavelength of light,
l=4.6 m
A.We have to find the distance between the two m=1 bright fringes

For first bright fringe, =1


The distance between two m=1 fringes

Hence, the distance between two m=1 fringes=2.95 m
B.For maximum number of fringes,


Substitute the values


Maximum number of bright fringes on the scree=
Answer:
<h3>a.</h3>
- After it has traveled through 1 cm :

- After it has traveled through 2 cm :

<h3>b.</h3>
- After it has traveled through 1 cm :

- After it has traveled through 2 cm :

Explanation:
<h2>
a.</h2>
For this problem, we can use the Beer-Lambert law. For constant attenuation coefficient
the formula is:

where I is the intensity of the beam,
is the incident intensity and x is the length of the material traveled.
For our problem, after travelling 1 cm:




After travelling 2 cm:




<h2>b</h2>
The optical density od is given by:
.
So, after travelling 1 cm:




After travelling 2 cm:




<span>In order for
an object to accelerate, a <u>force</u> must be applied. It follows Newton’s second
law of motion where it states that a body at rest remains at rest unless a
force is acted upon it. When you move an object, you are exerting a force onto
it. By exerting a force on the object, you are actually displacing it from its
initial position. You cannot apply force to the object without altering its
position. Keep in mind that when you exert work, you are exerting energy too. </span>