Answer:
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Answer:
![F=1.26*10^{-3}N](https://tex.z-dn.net/?f=F%3D1.26%2A10%5E%7B-3%7DN)
Explanation:
Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:
![F=\frac{kq_1q_2}{d^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq_1q_2%7D%7Bd%5E2%7D)
We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges(
) and inversely proportional to the square of the distance(d) that separates them.
Replacing the given values, where k is the Coulomb constant:
![F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B8.99%2A10%5E%7B9%7D%5Cfrac%7BN%5Ccdot%20m%5E2%7D%7BC%5E2%7D%28-30%2A10%5E%7B-9%7DC%29%28-30%2A10%5E%7B-9%7DC%29%7D%7B%288%2A10%5E%7B-2%7Dm%29%5E2%7D%5C%5CF%3D1.26%2A10%5E%7B-3%7DN)
The sum of potential energy<span> and kinetic </span><span>energy.
Hope I helped!</span>