Answer:
The magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N
Explanation:
Given;
speed of the electron, v = 8.0 × 10⁶ m/s
magnetic field strength, B = 2.5 T
angle of inclination of the field, θ = 60°
The magnetic force experienced by the electron in the magnetic field is given as;
F = qvBsinθ
where;
q is charge of electron = 1.6 x 10⁻¹⁹ C
B is strength of magnetic field
v is speed of the electron
Substitute the given values and solve for F
F = (1.6 x 10⁻¹⁹)( 8.0 × 10⁶)(2.5)sin60
F = 2.77 x 10⁻¹² N
Thus, the magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N
Answer:
Explanation:
We don't need the mass of the car in the equation to solve for final velocity, since the values given for the acceleration and the time it took to accelerate to that velocity are given. The equation we need is the one for acceleration, which is
We are solving for final velocity, we know the initial velocity is 0 (starting from rest), and the time to complete this acceleration (10 m/s/s) is 3 seconds:
which is the same thing as saying
so
v = 30 m/s
As seagull drops a shell from rest at a height of 12 m, so we use kinematic equation of motion,
Here, h is the height, u is initial velocity , v is final velocity and g is acceleration due to gravity.
Given, h = 12 m.
We take, 
and 
because seagull drops a shell from rest.
Therefore, the speed of shell when it hits the rocks,
Answer:
300 N
Explanation:
The net force acting on the arrow is given by Newton's Second Law:
where
m = 0.06 kg is the mass of the arrow
a = 5,000 m/s^2 is the acceleration of the arrow
Substituting the numbers into the equation, we find
Answer:
5.3 × 10^(-8) m
Explanation:
We are given;
Shear force; F = 400 N
Length of cube; L_o = 30 cm = 0.3 m
Shear modulus; S = 2.5 × 10^(10) N/m²
Now,the resulting relative displacement can be gotten from the formula;
F = A × S × Δx/L_o
Where Δx is resulting relative displacement
A is area.
Area of cube = (L_o)² = 0.3² = 0.09
Thus, making Δx the subject, we have;
Δx = (F × L_o)/(A × S)
Plugging in the relevant values;
Δx = (400 × 0.3)/(0.09 × 2.5 × 10^(10))
Δx = 5.3 × 10^(-8) m
