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daser333 [38]
3 years ago
6

One of the most efficient heat engines ever built is a coal-fired steam turbine in the Ohio River valley, operating between 1 87

0°C and 430°C.
(a) What is its maximum theoretical efficiency? %

(b) The actual efficiency of the engine is 42.0%. How much mechanical power does the engine deliver if it absorbs 1.30 105 J of energy each second from its hot reservoir?
Physics
1 answer:
k0ka [10]3 years ago
5 0

Answer:The answer

Explanation:

You might be interested in
What is 6.02 x 10^4 in standard notation
Vesnalui [34]
I believe you mean 6.02*10^7 but you want to shift the decimal 7 times to the right which would be 60200000 (:
4 0
3 years ago
!!HELP HELP!!
borishaifa [10]

Answer:

7.5s

Explanation:

Given parameters:

Velocity  = 30m/s

Deceleration  = 4m/s²

Unknown:

Time it takes for the car to come to complete rest  = ?

Solution:

 To solve this problem, we use the kinematics expression below:

        v  = u + at

 Since this is a deceleration

         v  = u - at

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

         v - u  = -at

         0  - 30  = -4 x t

              -30  = -4t

               t  = 7.5s

6 0
3 years ago
A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms.
victus00 [196]

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A)  = N₀(B)

N = N₀ e^{-\lambda t}

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ e^{-\lambda_1 t}

For B

N(B) = N(B)₀ e^{-\lambda_2 t}

N(A) = N(B) , for t = 2 h

N(A)₀ e^{-\lambda_1 t} = N(B)₀ e^{-\lambda_2 t}

N(A)₀ e^{-\lambda_1 t} = 5 x N₀(A)  e^{-\lambda_2 t}

e^{-\lambda_1 t} = 5  e^{-\lambda_2 t}

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

half life = .693 / λ

For A

.77 =  .693 / λ₁

λ₁ = .9 h⁻¹

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

Putting t = 2 h , λ₁ = .9 h⁻¹

e^{\lambda_2\times  2} = 5  e^{.9\times  2}

e^{\lambda_2\times  2} = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .

6 0
3 years ago
A 2018 Tesla Model S has a horsepower of 518. How many watts of power does this car model have?
elena-14-01-66 [18.8K]

Answer:

It depends on the model but these are the watts of each motor

Explanation:

Un motor: 258 HP (262 CV) Dual motor: 154 kW (209 CV) y 197 kW (268 CV). Performance: 154 kW (209 CV) y 225 kW (306 CV).

5 0
2 years ago
A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The blo
erik [133]

The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d

The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.

Therefore,

using Newtons third law

F - f = ma

a = v/t

t = d/v

F - f = m × v / t

F- f = m × \frac{v}{\frac{d}{v} }

F- f = m × v²/d

Therefore,

F- f = mv² / d

read more: brainly.com/question/18805877?referrer=searchResults

8 0
3 years ago
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