Pseudoscience means any various methods, theories, or systems
Answer:
- 416 kJ/mol
Explanation:
The standard enthalpy of the reaction (Δ
H
∘
rxn) is independent of the pathway, so it can be calculated by the enthalpy of formation of the reactants and the products:
Δ
H
∘
rxn = ∑n*Δ
H
∘f products - ∑n*Δ
H
∘f reactants
Where n is the number of moles in the balanced reaction. So, for the reaction given:
Na₂O(s) + 1/2O₂(g) → Na₂O₂(s)
Because O₂ is formed by only one elements, its Δ
H
∘f is 0 kJ/mol:
-89.0 = (1*(-505) - (1*Δ
H
∘fNa₂O)
Δ
H
∘fNa₂O = -505 + 89
Δ
H
∘fNa₂O = - 416 kJ/mol
Answer:
it would most likely occur
———————————————————————————————————————
Across a semi-permeable membrane that separates solutions of different concentrations
———————————————————————————————————————
this is because osmosis is the ‘net’ movement of molecules from a ‘region’ of ‘higher concentration’ to a ‘region’ of ‘lower concentration’ ‘down the concentration gradient’.
According to the <span>Le
Chatelier's Principle, if a condition of system is changed, then the system try
to become equilibrium again by correcting that change.
N2(g) + 3H2(g) ⇄<span> 2NH3(g)
If H2(g) is added, then the concentration of H2(g) is high in the system. So
the system tries to reduce it and become to equilibrium
state. Hence to reduce that H2(g) the forward reaction is promoted. Then
Concentration of product, NH3 gas
is increased.</span></span>
