Answer:
There are a total of 12 combinations you can get
Step-by-step explanation:I counted
Answer:
974
Step-by-step explanation:
(91.01)*(10.7)
91.01*(10.7)
91.01*10.7
973.80700
974
Consider,

. Let's say

then the problem reduces to

. (Do you understand this step?)
So then replacing a again with our definition we get,

.
I believe the correct number is 88.
we are given

Firstly, we will factor numerators and denominators

we can see that
n^2 -6 is factor on both numerator and denominator
so, it will get cancelled
and n^2 -6 can not be equal to 0
so, one of restriction is


we can simplify it

we know that denominator can not be zero


so, option-B.......Answer