If the length of a pendulum is doubled,what will be the change in its time period??

A ball is thrown upward with a speed of 40 m/s. Approximately how much time goes it take the ball to travel from the release loc

yulyashka [42]

Answer:

(I). The time at highest point 4.0 sec.

(II). It returns to back to its original height in 8.1 sec

Explanation:

Given that,

Velocity $v=40\ m/s$

(I). We need to calculate the time at highest point

Using equation of motion

$v=u+gt$

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

t = time

Put the value into the formula

$0=40-9.8t$

$-40=-9.8t$

$t=\dfrac{40}{9.8}$

$t=4.0\ sec$

(II). We know that, when the ball to travel from the initial point and reached at initial point then the displacement is zero.

We need to calculate the total time when it returns to back to its original height

Using equation of motion

$s=ut-\dfrac{1}{2}gt^2$

Where, s = displacement

g = acceleration due to gravity

t = time

u = velocity

Put the value in the equation

$0=40t-\dfrac{1}{2}9.8t^2$

$80t-9.8t^2=0$

$t=0, 8.1 sec$

Hence. (I). The time at highest point 4.0 sec.

(II). It returns to back to its original height in 8.1 sec

5 0

3 years ago

What is the speed of a wave if the wavelength is 200 m and the period is 20 s?

goblinko [34]

Here is your answer

We know that

Velocity = Wavelength/Time period

Here,

Wavelength = 200m

Time period= 20 secs

So,

Velocity= 200/20 m/s

v= 10m/s

HOPE IT IS USEFUL

6 0

3 years ago

What is the function of polarized glasses?.

evablogger [386]

The polarized glasses contain a special filter that blocks the glares and the hazes while driving through the sun or looking at the water, which makes your eyes more comfortable and makes you see better.

Hope this Helps! :)

8 0

4 years ago

distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm.

a_sh-v [17]

Answer:

The speed of the galaxy relative to the Earth is $3.09\times 10^6\ m/s$ .

Explanation:

We have,

(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.

(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

$v=c(\dfrac{\lambda'}{\lambda}-1)\\\\v=3\times 10^8\times (\dfrac{438.6 }{434.1 }-1)\\\\v=3\times 10^8\times (\dfrac{438.6}{434.1}-1)\\\\v=0.0103\cdot3\cdot10^{8}\\\\v=3.09\times 10^6\ m/s$

So, the speed of the galaxy relative to the Earth is $3.09\times 10^6\ m/s$ .

4 0

3 years ago

Four point charges are individually brought from infinity and placed at the corners of a square. Each charge has the identical v

Brut [27]

To solve this problem we will apply the concept of voltage given by Coulomb's laws. From there we will define the charges and the distance, and we will obtain the total value of the potential difference in the system.

The length of diagonal is given as

$l = 2a$