1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mars1129 [50]
4 years ago
14

Regions in the milky way where density waves have caused gas clouds to crash into each other are called

Physics
1 answer:
Mandarinka [93]4 years ago
7 0
Regions in the milky way where density waves have caused gas clouds to crash into each other are called clumps.Clumps are molecular clouds (interstellar clouds) with higher density,where lots of dust and gs cores resides. These clouds are the beginning of stars.
You might be interested in
A 0.144 kg baseball moving 28.0 m/s strikes a stationary 5.25 kg brick resting on small rollers so it moves without significant
zlopas [31]

(a) Only momentum conservation

In order to find the speed of the ball, momentum conservation is enough. In fact, we have the following equation:

m u + M U = m v + M V

where

m is the mass of the baseball

u is the initial velocity of the baseball

M is the mass of the brick

U is the initial velocity of the brick

v is the final velocity of the baseball

V is the final velocity of the brick

In this problem we already know the value of: m, u, M, U, and V. Therefore, there is only one unknown value, v: so this equation is enough to find its value.

(b) 12.1 m/s

Using the equation of conservation of momentum written in the previous part:

m u + M U = m v + M V

where we have:

m = 0.144 kg

u = +28.0 m/s (forward)

M = 5.25 kg

U = 0

V = +1.1 m/s (forward)

We can solve the equation to find v, the velocity of the ball:

v=\frac{mu-MV}{m}=\frac{(0.144 kg)(+28.0 m/s)-(5.25 kg)(+1.1 m/s)}{0.144 kg}=-12.1 m/s

And the sign indicates that the ball bounces backward, so the speed is 12.1 m/s.

(c)  56.4 J, 13.7 J

The total mechanical energy before the collision is just equal to the kinetic energy of the baseball, since the brick is at rest; so:

E_i = \frac{1}{2}mu^2 = \frac{1}{2}(0.144 kg)(28.0 m/s)^2=56.4 J

The total mechanical energy after the collision instead is equal to the sum of the kinetic energies of the ball and the brick after the collision:

E_f = \frac{1}{2}mv^2 + \frac{1}{2}MV^2 = \frac{1}{2}(0.144 kg)(12.1 m/s)^2 + \frac{1}{2}(5.25 kg)(1.1 m/s)^2=13.7 J

(d)

A collision is:

- elastic when the total mechanical energy is conserved before and after the collision

- inelastic when the total mechanical energy is NOT conserved before and after the collision

In this problem we have:

- Energy before the collision: 56.4 J

- Energy after the collision: 13.7 J

Since energy is not conserved, this is an inelastic collision.

(e) No

As shown in part (c) and (d), the kinetic energy of the system is not conserved. This is due to the fact that in inelastic collisions (such as this one), there are some internal/frictional forces that act on the system, and that cause the dissipation of part of the initial energy of the system. This energy is not destroyed (since energy cannot be created or destroyed), but it is simply converted into other forms of energy (mainly heat and sound).

8 0
4 years ago
Calculate the gravitational force between a 10 kg ball and 20 kg ball
elena-s [515]

Answer:

5.34\cdot 10^{-10} N

Explanation:

The gravitational force is an attractive force exerted between any objects with mass.

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the two objects

In this problem, we have:

m_1 = 10 kg is the mass of the 1st ball

m_2 = 20 kg is the mass of the 2nd ball

r = 5 m is the separation

So, the gravitational force between them is

F=(6.67\cdot 10^{-11})\frac{(10)(20)}{5^2}=5.34\cdot 10^{-10} N

7 0
3 years ago
an ocean wave has a wavelength of 16 meters and a frequency of 0.31 waves per second. what is the spend of the wave
Svet_ta [14]

Answer:

51.1 is the answer

Explanation:

7 0
2 years ago
Suppose that the average speed (vrms) of carbon dioxide molecules (molar mass 44.0 g/mol) in a flame is found to be 2.67 105 m/s
34kurt

Answer:

T = 1.26 \times 10^8 K

Explanation:

As we know that rms speed of ideal gas is given by the formula

v_{rms} = \sqrt{\frac{3RT}{M}}

here we know that

v_{rms} = 2.67 \times 10^5 m/s

molecular mass of gas is given as

M = 44 g/mol = 0.044 kg/mol

now from above formula we have

2.67\times 10^5 = \sqrt{\frac{3(8.31)T}{0.044}}

now we have

T = 1.26 \times 10^8 K

7 0
4 years ago
What is the formula for acceleration.
Trava [24]
The formula for acceleration, or average acceleration, is a=(vf-vi) divided by (tf-ti) .
a= Acceleration (or average acceleration
vf= Final Velocity
vi= Initial Velocity
tf= Final Time
ti= Initial Time
hope i helped you out!
3 0
3 years ago
Other questions:
  • PHYSICS PLEASE HELP
    12·2 answers
  • A bag of groceries has a weight of 44 newtons. Find its approximate weight in kilograms.
    14·1 answer
  • If you were to apply a force of 15N to a medicine ball with a mass of 10kg, what would its acceleration be
    8·1 answer
  • Why are the orbitals shells called s, p, d, f, etc.? Is there a reason?
    15·1 answer
  • An open-delta three-phase transformer system has one transformer center-tapped to provide a neutral for single-phase voltages. I
    13·1 answer
  • Which method of calculating volume would you use if the object is irregulary shaped?
    13·1 answer
  • What is the average speed between 5 seconds and 15 seconds?
    7·2 answers
  • Protons, neutrons, and electrons are the 3 particles that make up an atom.<br> True or False
    7·1 answer
  • How does magnetic compass help to identify directions​
    7·1 answer
  • e) A escalator carries 60 people of average mass 70kg to a height of 5m in one minute. Find the power needed to do this? 4​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!