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Verdich [7]
3 years ago
10

A bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. During the

first part, she rides for 22 minutes at an average speed of 7.2 m/s. During the second part, she rides for 36 minutes at an average speed of 5.1 m/s. Finally, during the third part, she rides for 8.0 minutes at an average speed of 13 m/s. (a) How far has the bicyclist traveled during the entire trip? (b) What is her average velocity for the trip? (Ans: a)26.7km, b) 6.74m/s)
Physics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

a

The total distance traveled is D  = 26760 \ m

b

The average velocity is  v_{avg} =  6.8 \ m/s

Explanation:

From the question we are told that

     The time taken for first part t_1 =  22 \ minutes = 22*60 = 1320 \ s

      The speed for the first part is  v_1 =  7.2 \ m/s

        The time taken for second part is t_2 =  36 \ minutes =  2160 \ s

        The speed for the second  part is  v_2 =  5.1 \ m/s

         The time taken for third  part is  t_3 =  8 \ minutes = 480 \ s  

          The speed for the third  part is  v_3 =  13 m/s

Generally

        distance(D)  =  velocity * time

Therefore the total distance traveled is  

         D  =  (v_1 * t_1) + (v_2 * t_2 ) + (v_3 * t_3)

substituting values

        D  =  (7.2 * 1320) + (5.1 * 2160) + (13 * 480)

        D  = 26760 \ m

Generally the average velocity is mathematically represented as

        v_{avg} =  \frac{D}{t_{total}}

Where t_{total} is the total time taken which is mathematically represented as

       t_{total}  =  1320 + 2160 + 480

      t_{total}  =3960\ s

The average velocity is

        v_{avg} =  \frac{26760}{3960}

        v_{avg} =  6.8 \ m/s

   

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