By putting this special transportation plastic on the bottom of the sled, because the transportation plastic is slick. that is what the transport bins slide around on. (p.s) the plastic is really expensive!
Answer:
0.363999909622
Explanation:
F = Force
m = Mass = 15.6 g
C = Drag coefficient
ρ = Density of air = 1.21 kg/m³
A = Surface area = ![\dfrac{\pi}{4}d^2](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpi%7D%7B4%7Dd%5E2)
v = Terminal velocity = ![v=210\ m/s](https://tex.z-dn.net/?f=v%3D210%5C%20m%2Fs)
s = Displacement = 150 m
![a=\dfrac{v^2-u^2}{2s}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2s%7D)
Force is given by
F = ma
![F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B1%7D%7B2%7D%5Crho%20CAv%5E2%5C%5C%5CRightarrow%20ma%3D%5Cdfrac%7B1%7D%7B2%7D%5Crho%20CAv%5E2%5C%5C%5CRightarrow%20m%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2s%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Crho%20CAv%5E2%5C%5C%5CRightarrow%20C%3D2%5Ctimes%20m%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2s%7D%5Ctimes%5Cdfrac%7B1%7D%7B%5Crho%20Av%5E2%7D%5C%5C%5CRightarrow%20C%3D2%5Ctimes15.6%5Ctimes%2010%5E%7B-3%7D%5Cdfrac%7B210%5E2-250%5E2%7D%7B2%5Ctimes%20150%7D%5Ctimes%5Cdfrac%7B1%7D%7B1.21%5Ctimes%5Cdfrac%7B%5Cpi%7D%7B4%7D%5Ctimes%20%2811.2%5Ctimes%2010%5E%7B-3%7D%29%5E2%28210%29%5E2%7D%5C%5C%5CRightarrow%20C%3D-0.363999909622)
The drag coefficient is 0.363999909622 (ignoring negative sign)
Mechanical energy is the sum of kinetic energy and potential energy
The bed load moves the slowest from all the parts of the stream's sediment. It consists of particles suspended that are suspended and float around the bed. This part is the slowest in motion, as it rolls, and moves with the flow. The particles near the bed are not dissolved so they settle at the bottom and move with the stream.
Answer: a) 0.315 (V/L)
Explanation:
From Conservation of angular momentum, we know that
L1 = L2 ,
Therefore MV L/2 = ( Irod + Ib) x W
M/4 x V x L/2 = (M (L/2)^2 + 1/3xMxL^2) x W
M/8 X VL = (ML^2/16 + ML^2 /3 )
After elimination we have,
V/8 = 19/48 x L x W
W = 48/8 x V/19L = 6/19 x V/L
Therefore W = (0.136)X V/L