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Vladimir79 [104]
3 years ago
15

How could the action force of a canoe moving through water be increased?.

Physics
1 answer:
BaLLatris [955]3 years ago
4 0
There are several actions that can be used to increase the action force of a canoe that is moving through water. One can increase the rate of striking or strike harder than before with a bigger paddle. Using a lighter canoe can also be helpful for increasing the speed. I hope the answer comes to your help.
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You are taking a turn at 30.0 m/s on a ramp of radius 25.0 m. What is your acceleration?
Nat2105 [25]

Acceleration = v^2 / r

Acceleration = 30^2/25

Acceleration = 900/25

Acceleration = 36 m/s^2

6 0
2 years ago
The United States and South Korean soccer teams are playing in the first round of the World Cup. An American kicks the ball, giv
garik1379 [7]

Answer:

Vf = 3.67 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} ^{2} =v_{i} ^{2} -(2*a*x)

where:

Vf = final velocity [m/s]

Vi = initial velocity = 4.3 [m/s]

a = acceleration or desacceleration = 0.5 [m/s²]

x = distance = 5 [m]

Note: The negative sign in the above equation means that the velocity of the ball is decreasing (desacceleration).

Now replacing:

Vf² = (4.3)² - (2*0.5*5)

Vf² = 18.49 - 5

Vf² = 13.49

using the square root, we have.

Vf = 3.67 [m/s]

8 0
2 years ago
5. A sled with no initial velocity accelerates at a rate of 5.0 m/s2 down a hill. How
ad-work [718]

Answer:

60 m/s

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a =  \frac{vf - vi}{t}

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60 = vf

6 0
3 years ago
How many joules of electrical energy is transferred per second by 6V 0.5 A lamp?
Degger [83]

When you ask for "joules per second", you're asking for "watts".
The rate of energy "transfer" is 'power'.  In this case, the light bulb
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Electrical power = (voltage) x (current) =

                              (6 volts) x (0.5 ampere) =

                                          3 watts  =  3 joules per second.
 
4 0
3 years ago
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5 0
2 years ago
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