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Vlad [161]
3 years ago
14

Which word completes the blank in the following statement?

Chemistry
1 answer:
Dvinal [7]3 years ago
8 0
The answer should be an electrical circut
i think thats how you spell it

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Amount of moles in 3.34x10^34 formula units of Cu(OH)2
Naily [24]

 The amount of  moles in  3.34 x10³⁴  formula unit of Cu(OH)₂ is 5.55 × 10¹⁰  moles

  <u><em>calculation</em></u>

 The  amount  of  moles  is calculated  using  the Avogadro's  law   constant

That  is  1  moles =  6.02 × 10²³  formula units

                 ? moles = 3.34 × 10³⁴ formula  units

<em>by cross  multiplication</em>

= {1 mole  ×3.34 ×10³⁴  formula units ] / 6.02 × 10²³ formula units}  = 5.55 ×10¹⁰  moles


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The best solution for the problem of pollution by man-made technologies A. cannot involve anyone who is not a technology expert
Ber [7]

Answer:

is likely to come from collaborative efforts by technology experts and experts on pollution.

Explanation:

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3 years ago
Hsgsfqg hsagdjhagsydt ahsgdytratdw
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Answer:

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2 years ago
What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
dusya [7]

Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

  • C: 12.011 g/mol
  • H: 1.008 g/mol
  • O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

3. Calculate Molarity

Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

1 mole per liter is also equal to 1 M.

molarity = 0.17 \ M \ C_6H_12O_6

3 0
2 years ago
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