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Agata [3.3K]
3 years ago
12

Solve the inequality 2x + 8 < 5x − 4.

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0

The solution to this inequality is 4 < x or x > 4.

In order to solve this, follow the steps to solving an equation with one variable. The steps are below for you.

2x + 8 < 5x - 4 ------> Subtract 2x from both sides

8 < 3x - 4 -----> Add 4 to both sides

12 < 3x -----> Divide both sides by 3

4 < x

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A fish tank contains 3 of water and is one-fourth full. How many quarts of water does the fish tank hold all together?
DIA [1.3K]

The fish tank holds 48 quarts of water

8 0
2 years ago
According to a​ report, 67.5​% of murders are committed with a firearm. ​(a) If 200 murders are randomly​ selected, how many wou
kolezko [41]

Answer: The answer is 135 murders.

Step-by-step explanation: The report tells us that statistically 67.5% of murders are committed using a firearm. It follows therefore that in a sample of 200 randomly selected murders, one would expect that 67.5% of those would be by a firearm. \frac{67.5}{100} * 200 = 135.

It would certainly be higher that the expected value based on previous data collected but it would not be unusual because one sample may have a higher than "normal" amount of murders by firearm. Statistics aren't going to be exact for every sample.

8 0
3 years ago
When I add a number to another number four times as big, the result is 30. find the first number
Alex73 [517]

Answer:

x = 6

Step-by-step explanation:

Let x = first number

x+4x = 30

5x = 30

Divide by 5

5x/5 =30/5

x = 6

3 0
2 years ago
Read 2 more answers
A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l
tankabanditka [31]

Answer:

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 95

Given that the standard deviation of the Population = 5

Let 'X' be the random variable in a normal distribution

Let X⁻ = 96.3

Given that the size 'n' = 84 monitors

<u><em>Step(ii):-</em></u>

<u><em>The Empirical rule</em></u>

         Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

        Z = \frac{96.3 - 95}{\frac{5}{\sqrt{84} } }

       Z = 2.383

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

    P(X⁻ ≥ 96.3) = P(Z≥2.383)

                      =  1- P( Z<2.383)

                      =  1-( 0.5 -+A(2.38))

                      = 0.5 - A(2.38)

                     = 0.5 -0.4913

                    = 0.0087

<u><em>Final answer:-</em></u>

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

3 0
2 years ago
1.12- 2 3/5 QUICK!!!​
Rzqust [24]

Answer:

47/5 or 9 2/5

Step-by-step explanation:

12/1-13/5

60-13/5

=47/5

7 0
2 years ago
Read 2 more answers
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