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shutvik [7]
3 years ago
6

٠Light bulb A is rated at 60 W and light bulb B is rated at 100 W. Both are designed to operate at 110 V. Which statement is cor

rect?
A-The 60 W bulb has a greater resistance and greater current than the 100 W bulb.

B-The 60 W bulb has a greater resistance and smaller current than the 100 W bulb.

C-We need to know the resistivities of the filaments to answer this question.

D-The 60 W bulb has a smaller resistance and greater current than the 100 W bulb.

F-The 60 W bulb has a smaller resistance and smaller current than the 100 W bulb
Physics
1 answer:
leva [86]3 years ago
8 0

Answer:B

Explanation:

Power=p

Voltage=v

Resistance=r

Voltage for both:110v

For 60 watts bulb:

Resistance=v^2/p

Resistance=110^2/60

Resistance=(110x110)/60

Resistance=12100/60

Resistance=201.7 ohms

Current=power/voltage

Current=60/110

Current=0.55 amperes

For 100watts bulb:

Resistance=v^2/p

Resistance=110^2/100

Resistance=(110 x 110)/100

Resistance=(12100)/100

Resistance =121 ohms

Current=power/voltage

Current=100/110

Current=0.91

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At the same moment, one rock is dropped and one is thrown downward with an initial velocity of 29m/s from the top of a building
Inessa [10]

Answer:

The thrown rock strike 2.42 seconds earlier.

Explanation:

This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:

x=vo*t+\frac{1}{2} a*t^2\\where\\x=distance\\vo=initial velocity\\a=acceleration

So now we have an equation and unkown value.

for the thrown rock

\frac{1}{2}(9.8)*t^2+29*t-300=0

for the dropped rock

\frac{1}{2}(9.8)*t^2+0*t-300=0

solving both equation with the quadratic formula:

\frac{-b\±\sqrt{b^2-4*a*c} }{2*a}

we have:

the thrown rock arrives on t=5.4 sec

the dropped rock arrives on t=7.82 sec

so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)

6 0
3 years ago
1. 1500j of work was done to move a box 20m. What force was applied to the box ?
Fantom [35]

Answer:

1. 75N

2. 67,983 J (=67.98 kJ)

Explanation:

1. Work = Force x Distance

we are given that Work = 1,500J and Distance = 20m

hence,

Work = Force x Distance

1,500 = Force x 20

Force = 1,500 ÷ 20 = 75N

2. Potential Energy, PE = mass x gravity x change in height

we are given that mass = 165 kg and change in height = 42m

assuming that gravity, g = 9.81 m/s²

Potential Energy, PE = mass x gravity x change in height

Potential Energy, PE = 165 x 9.81 x 42 = 67,983 J (=67.98 kJ)

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3 years ago
A magnetic field of magnitude 0.550 T is directed parallel to the plane of a circular loop of radius 43.0 cm. A current of 5.80
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Explanation:

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The magnitude of magnetic field, B = 0.55 T

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The current in the loop, I = 5.8 mA = 0.0058 A

We need to find the magnetic moment of the loop. It is given by the relation as follows :

\mu = AI\\\\\mu=\pi r^2\times I

Put all the values,

\mu=\pi \times (0.43)^2\times 0.0058\\\\=3.36\times 10^{-3}\ A-m^2

So, the magnetic moment of the loop is equal to3.36\times 10^{-3}\ A-m^2.

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Which letter BEST shows how to measure amplitude?
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