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shutvik [7]
3 years ago
6

٠Light bulb A is rated at 60 W and light bulb B is rated at 100 W. Both are designed to operate at 110 V. Which statement is cor

rect?
A-The 60 W bulb has a greater resistance and greater current than the 100 W bulb.

B-The 60 W bulb has a greater resistance and smaller current than the 100 W bulb.

C-We need to know the resistivities of the filaments to answer this question.

D-The 60 W bulb has a smaller resistance and greater current than the 100 W bulb.

F-The 60 W bulb has a smaller resistance and smaller current than the 100 W bulb
Physics
1 answer:
leva [86]3 years ago
8 0

Answer:B

Explanation:

Power=p

Voltage=v

Resistance=r

Voltage for both:110v

For 60 watts bulb:

Resistance=v^2/p

Resistance=110^2/60

Resistance=(110x110)/60

Resistance=12100/60

Resistance=201.7 ohms

Current=power/voltage

Current=60/110

Current=0.55 amperes

For 100watts bulb:

Resistance=v^2/p

Resistance=110^2/100

Resistance=(110 x 110)/100

Resistance=(12100)/100

Resistance =121 ohms

Current=power/voltage

Current=100/110

Current=0.91

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b) the inductor current is 0.5 mA

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25V =  25V × sin( 2.5 × 10⁶ s⁻¹ × t )

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{ sin(ωt) = 1 )

I(t) = V₀√(C/L)

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I(t) = 25V × √( ( 8.0 × 10⁻¹² F ) / ( 20 × 10⁻³ H ) )

I(t) = 25 × 0.00002

I(t) = 0.0005 A

I(t) = 0.5 mA

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