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Phantasy [73]
3 years ago
8

Which information would be required to determine the mass number of nitrogen

Physics
1 answer:
algol133 years ago
6 0
Looking at the bottom of the element on the periodic table.
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A shopping cart is initially at rest when it undergoes a constant acceleration. After
Luba_88 [7]
The answer is A.3.3 m/s2
4 0
3 years ago
(Brainliest) How are radio waves used in cell phone wireless communication technology?
poizon [28]

Radio waves are used in cell phone wireless communication by this: Radio waves are released from the cell phone and travel to satellites in the stratosphere. After they reach the satellite, they are redirected to the recipient of the call/text.

Hope this helps! Can I have brainliest please?

5 0
3 years ago
A small electronic device is rated at 0.16 W when connected to 115 V. What is the resistance of this device?
Ierofanga [76]

Answer:

150156.25 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of electric current in a circuit. The S.I unit of resistance is Ohm's (Ω)

The expression for resistance is given as

P = V²/R................ equation 1

Where P = power, V = Voltage, R = Resistance.

Making R the subject of the equation,

R = V²/P.................. Equation 2

Given: V = 115 V , P = 0.16 W.

Substitute into equation 2

R = 155²/0.16

R = 150156.25 Ω

Hence,

The resistance = 150156.25 Ω

8 0
3 years ago
Read 2 more answers
. A person weighing 750 N gets on an elevator.
Kobotan [32]

 

F = 750 N  (Force)

d = 10 m  (displacement )

t = 25 s   (time)

L = ?   (Mechanical work )  =  (Energy)

P = ?   (Power)

Solve:

L = F × d = 750 × 10 = 7500 Joules

P = L / t = 7500 / 25 = 300 Watts

5 0
2 years ago
Lasers can be constructed that produce an extremely high intensity electromagnetic wave for a brief time—called pulsed lasers. T
alex41 [277]

Answer:

30643 J

Explanation:

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

t = Time taken = 1 ns

c = Speed of light = 3\times 10^8\ m/s

E_0 = Maximum electric field strength = 1.52\times 10^{11}\ V/m

A = Area = 1\ mm^2

Magnitude of magnetic field is given by

B_0=\dfrac{E_0}{c}\\\Rightarrow B_0=\dfrac{1.52\times 10^{11}}{3\times 10^8}\\\Rightarrow B_0=506.67\ T

Intensity is given by

I=\dfrac{cB_0^2}{2\mu_0}\\\Rightarrow I=\dfrac{3\times 10^8\times 506.67^2}{2\times 4\pi \times 10^{-7}}\\\Rightarrow I=3.0643\times 10^{19}\ W/m^2

Power, intensity and time have the relation

E=IAt\\\Rightarrow E=3.0643\times 10^{19}\times 1\times 10^{-6}\times 1\times 10^{-9}\\\Rightarrow E=30643\ J

The energy it delivers is 30643 J

4 0
3 years ago
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