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laila [671]
3 years ago
10

A spring of negligible mass and force constant k = 410 N/m is hung vertically, and a 0.200 kg pan is suspended from its lower en

d. A butcher drops a 2.5 kg steak onto the pan from a height of 0.50 m. The steak makes a totally inelastic collision with the pan and sets the system into vertical SHM
1. What is the speed of the pan and steak immediately after the collision?

2. What is the amplitude of the subsequent motion?

3. What is the period of that motion?
Physics
1 answer:
IgorC [24]3 years ago
8 0

Answer:

1) 2.9m/s

2)0.235cm

3)0.509s

Explanation:

1. moments are conserved, when the steak hits the pan:

velocity 'v' of the steak:  

v = √(2gh) = √(2*9.81*0.5) = 3.13 m/s

velocity pan + steak is

v =m_1v_1/(m_1+m_2)= 2.5*3.13/(2.7) = <u>2.9 m/s </u>

<u />

2.initial kinetic energy of pan + steak = spring energy  

1/2 mv² = 1/2 kA²  

where, A = amplitude  

2.7 x 2.9² = 410 x A²

A²=22.707/410

A = 0.235 cm

3. T = 2π√(m/k) = 2π√(2.7/410) = 0.509 s

Therefore, the period of that motion is 0.509s

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(1.b) The intensity of the sound wave as it reaches the person listening is 0.02 W/m².

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<h3>Surface area being vibrated</h3>

The surface area being vibrated by the time the sound reaches the listener is calculated as follows;

A = 4πr²

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A = 5,026.55 m²

<h3>Intensity of the sound</h3>

The intensity of the sound is calculated as follows;

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<h3>Relative intensity of the sound</h3>

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v= 331.3\sqrt{1 + \frac{T}{273} } \\\\v = 331.3\sqrt{1 + \frac{15}{273} } \\\\v = 340.3 \ m/s

<h3>Frequency of the sound</h3>

The frequency of the sound heard is determined by applying Doppler effect.

f_o = f_s(\frac{v \pm v_0}{v \pm v_s} )

where;

  • -v₀ is velocity of the observer moving away from the source
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  • fs is the source frequency
  • fo is the observed frequency
  • v is speed of sound

f_0 = f_s(\frac{v-v_0}{v- v_s} )

f_0 = 512(\frac{340.3 - 10}{340.3 - 65} )\\\\f_0 = 614.3 \ Hz

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