35g of HF was prepared by reacting 112g of CaF2 with an excess of H2SO4 calculate the percentage yield
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The volume of the liquid from the graduated cylinder is 22.5 mL
The last option (22.5 mL) is the correct option
The question seems to be incomplete
The image that completes the question is shown in the attachment below.
From the image, we observe that the liquid meniscus is between the 20 mL and 25 mL marks. That means the volume will lie in this range.
NOTE: The meniscus of a liquid is the upward or downward curve seen at the top of a liquid in a container.
The type of curve shown in the image is a concave meniscus and the volume of the liquid is read from the bottom of the curve.
To read the value from the graduated cylinder, we will first determine the difference between two consecutive lines. Between the 20 mL and 25 mL mark (two thick lines), we have 5 spaces separated by thin lines.
The measure between two consecutive lines is the difference between two thick lines divided by number of spaces between them
∴ The measure between two consecutive lines = (25mL - 20mL) ÷ 5
The measure between two consecutive lines = 5mL ÷ 5 = 1 mL
Now, to read the position of the liquid,
Starting from the 20 mL mark, the liquid exceeds two more lines + half way to the next line ( that is 2mL + 0.5 mL)
∴ The position of the liquid is 20 mL + 2mL + 0.5 mL = 22.5 mL
Hence, the volume of the liquid from the graduated cylinder is 22.5 mL
Learn more here: brainly.com/question/19240870
Answer:
0.01M
Explanation:
Given paramters:
Volume of FeCl₂ = ?
Concentration = 0.945M
Number of molecules of O₂ = 4.32 x 10²¹molecules
Solution:
The balanced reaction equation is given below:
4FeCl₂ + 3O₂ → 2Fe₂O₃ + 4Cl₂
Now, to solve the problem we use mole relationship between the compounds.
We work from the known to the unknown compounds. Here, the known is the oxygen gas because from the given parameters we can estimate the number of moles of the reacting gas.
number of moles of O₂ =
number of moles of O₂ =
number of moles of O₂ = 0.007mole
now, from the reaction equation we find the number of moles of the FeCl₂:
3 mole of O₂ reacted with 4 moles of FeCl₂
0.007mole of O₂ reacted with = 0.0096mole O₂
Now to find the volume of FeCl₂ we use the expression below;
volume of FeCl₂ =
=
= 0.01L