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Arlecino [84]
3 years ago
6

A cylindrical specimen of some metal alloy having an elastic modulus of 126 GPa and an original cross-sectional diameter of 3.4

mm will experience only elastic deformation when a tensile load of 2130 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.45 mm.
Chemistry
1 answer:
Delvig [45]3 years ago
5 0

Answer:

The maximum length of the specimen before deformation is 240.64 mm

Explanation:

Strain = stress ÷ elastic modulus

stress = load ÷ area

load = 2130 N

diameter = 3.4 mm = 3.4×10^-3 m

area = πd^2/4 = 3.142 × (3.4×10^-3)^2/4 = 9.08038×10^-6 m^2

stress = 2130 N ÷ 9.08038×10^-6 m^2 = 2.35×10^8 N/m^2

elastic modulus = 126 GPa = 126×10^9 Pa

Strain = 2.35×10^8 ÷ 126×10^9 = 0.00187

Length = extension ÷ strain = 0.45 mm ÷ 0.00187 = 240.64 mm

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Talja [164]

Answer:

B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

Explanation:

Hello,

In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.

Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.

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8 0
3 years ago
Read 2 more answers
Determine the molality of a solution of methanol dissolved in ethanol for which the mole fraction of methanol is 0.135. Give you
Alja [10]

<u>Answer:</u> The molality of the solution is 0.11 m

<u>Explanation:</u>

We are given:

Mole fraction of methanol = 0.135

This means that 0.135 moles of methanol is present in 1 mole of a solution

Moles of ethanol = 1 - 0.135 = 0.865 moles

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of ethanol = 0.865 moles

Molar mass of ethanol = 46 g/mol

0.865mol=\frac{\text{Mass of ethanol}}{46g/mol}\\\\\text{Mass of ethanol}=(0.865mol\times 46g/mol}=39.79g

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (methanol) = 0.135 g

M_{solute} = Molar mass of solute (methanol) = 32 g/mol

W_{solvent} = Mass of solvent (ethanol) = 39.79 g

Putting values in above equation, we get:

\text{Molality of methanol}=\frac{0.135\times 1000}{32\times 39.79}\\\\\text{Molality of methanol}=0.106m\approx 0.11m

Hence, the molality of the solution is 0.11 m

6 0
4 years ago
Hello I need help very bad!!!
Oksanka [162]

D. Cell membrane: surrounds a cell and allows substances to pass in and out

6 0
3 years ago
PLEASEEE HELPPP!!!!!!
chubhunter [2.5K]

Answer:

A

Explanation:

Cs has a higher rate of reaction because it's easier to remove an electron from it, thereby leading to faster reactivity

5 0
3 years ago
Read 2 more answers
(05.02 LC)<br><br> How many moles of each element are in one mole of Sr(HCO3)2? (3 points)
Nina [5.8K]

Answer:

The number of moles of Sr in one mole of Sr(HCO₃)₂ = 1 mole

The number of moles of H in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of C in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of O in one mole of Sr(HCO₃)₂ = 6 moles

Explanation:

The given chemical formula of the compound is Sr(HCO₃)₂

The number of atoms of Sr in the compound = 1

The number of atoms of H in the compound = 2

The number of atoms of C in the compound = 2

The number of atoms of O in the compound = 6

The number of atoms of each element present in each formula unit of Sr(HCO₃)₂ is proportional to the number of moles of each atom in one mole of Sr(HCO₃)₂

Therefore;

The number of moles of Sr in one mole of Sr(HCO₃)₂ = 1 mole

The number of moles of H in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of C in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of O in one mole of Sr(HCO₃)₂ = 6 moles.

5 0
3 years ago
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