Answer: Incoherent question
Explanation: This is an act of plagiarism at subjecting the tutor to unnecessary stress at answering the purported question.
Answer:
domestic, public, commercial, and industrial uses.
Answer:
D. Measure the voltage on the conductor with a known good meter
Explanation:
Answer:
1) q=18414.93 W
2) C=12920$
Explanation:
Given data:
pipe length L=25m
pipe diameter D=100mm =0.1 m
air temperature
=
=25
°C.....= 298.15k
pipe surface temp
=150
°C.....=423.15k
surface emissivity e= 0.8
boiler efficiency η=0.90
natural gas price Cg=$0.02 per MJ
1) Total heat loss and radiation heat loss combined
q=
q=
б(
^4-
^4)]....... (1)
б=5.67×10^-8 W/m^2K^4 (boltzmann constant)
area A =L.Dπ=25×0.1π=7.85 m^2
putting all these values in eq (1)
q=18414.93 W
2) suppose boiler is operating non stop annual energy loss will be
E=q.t
=18414.93.3600.24.365
=5.81×10^11 J
to find furnace energy consumption
Ef =E/η
=6.46×10^5 MJ
annual cost
C=Cg. Ef
=12920$
Answer:
Explanation:
Given that,
The area of glass
= 
The thickness of the glass 
The area of the styrofoam 
The thickness of the styrofoam 
The thermal conductivity of the glass 
The thermal conductivity of the styrofoam 
Inside and outside temperature difference is ΔT
The heat loss due to conduction in the window is

The heat loss due to conduction in the wall is

The net heat loss of the wall and the window is

The percentage of heat lost by the window is
