Answer:
Change in kinetic energy: 13479.77 J
Percentage change in kinetic energy = 99.85%
Explanation:
Change in momentum when the projectile becomes embedded in the block will be 0.
This means:
here subscript P means projectile, and subscript B means block.
Solving this equation we get:
(0.075 * 600) + (50 * 0) = (0.075 + 50) * V
Using this velocity we can compute the change in kinetic energy:
Initial kinetic energy = 0.5 * m * v^2
Initial kinetic energy = 0.5 * 0.075 * 600^2
Initial kinetic energy = 13500 J
Final Kinetic energy = 0.5 * m * v^2
Mass (m) = mass of block + mass of projectile = 50.075 kg
Final velocity v = 0.899 m/s
Final Kinetic Energy = 0.5 * 50.075 * 0.899^2
Final Kinetic Energy = 20.235 J
Change in kinetic energy = 13500 - 20.235 = 13479.77 J
Percentage change of kinetic energy = (13479.77 / 13500) * 100
Percentage change of kinetic energy = 99.85 %
