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3 years ago

I need help, Now please

Mathematics

1 answer:

Sav [38]3 years ago

7 0

Answer
D

Explanation:

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SOMEONE NEEDS TO EXPLAIN WHY 1.40 DIDNT WORK ON MY QUESTION 2.1/1.488

Zanzabum

My calculator shows that

(2.1)/(1.488) = 1.41129

which is approximate. If you want the result to two decimal places, then it would be 1.41 and not 1.40

Try 1.41 and it should work out, assuming your teacher wants two decimal places.

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2 years ago

A jar contains 4 green marbles and 3 blue marbles of the same size and shape. rachel will randomly pull 2 marbles from the bag a

vagabundo [1.1K]

Probably most likely 1.25% because in the question it doesn't say there is any blue marbles.

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3 years ago

Need help with inscribed angles If M

Bogdan [553]

Given:

In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and $m\angle BCD=30^\circ$ .

To find:

The $m\angle AOB$ .

Solution:

If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.

We have, DC is parallel to BA and BC is the transversal line.

$\angle OBA\cong \angle BCD$ [Alternate interior angles]

$m\angle OBA=m\angle BCD$

$m\angle OBA=30^\circ$

In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.

We know that base angles of an isosceles triangle are congruent.

$\angle OAB\cong \angle OBA$ [Base angles of an isosceles triangle]

$m\angle OAB=m\angle OBA$

$m\angle OAB=30^\circ$

In triangle AOB,

$m\angle OAB+m\angle OBA+m\angle AOB=180^\circ$

$30^\circ+30^\circ+m\angle AOB=180^\circ$

$60^\circ+m\angle AOB=180^\circ$

$m\angle AOB=180^\circ-60^\circ$

$m\angle AOB=120^\circ$

Therefore, the measure of angle AOB is 120 degrees.

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3 years ago

Given: f(x) = 2x-1 and g(x) = 2x-3<br> Find:<br> (fog)(x)<br> HELP PLEASEE!!

Murljashka [212]

Answer:

(fog)(x) = 4x - 7

Step-by-step explanation:

f(x) = 2x-1 and g(x) = 2x-3;

(fog)(x) = f(g(x)

= f(2x - 3) = 2(2x - 3) - 1

= 4x - 6 - 1

= 4x - 7

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3 years ago

Which of the following formulas would find the surface area of a right cylinder

Sliva [168]

Answer:

A and B

Step-by-step explanation:

Because the surface area is $\pi r^2*2\pi rh$

BA is the base, so $BA + 2\pi rh$ also works.

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3 years ago