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3 years ago

Can you help me with #3 please

Mathematics

1 answer:

sveticcg [70]3 years ago

5 0

We have two terms: 3x^3 and -9x

You have the correct GCF which is 3x. This GCF is factored out and placed to the left of the parenthesis, as you have done correctly so far.

Since 3x times x^2 is equal to 3x^3, this means that you have the proper first term inside the parenthesis. So far so good.

Where you make a mistake is with the second term inside the parenthesis. Notice how 3x times 2 is NOT equal to -9x

You need to fill in the blank:
3x times _________ = -9x

It turns out that -3 goes in that blank since 3x times -3 = -9x

This is why the final answer for problem 3 is 3x(x^2 - 3)

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A group of church members chartered a bus for $832. After making the arrangements, 6 more members decided to join the excursion

g100num [7]

Let x = # of original members
Cost per person (originally) = 832/x
Cost per person after 6 more people = 832/(x+6)
Solve 832/x=832/(x+6) +6 (because the cost was reduced by 6
Solve for x.
x = 26 or -32 (but x is number of members, so it can't be negative)
# of original members is 26.
Original cost is 832/26 = $32 per person.

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3 years ago

9), Eva can knit f of a scarf in an hour. Her sister takes of the time she

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Answer:

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3 years ago

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If polygon A is a parallelogram, and polygon B is a rectangle, which of the

Daniel [21]

Answer:

The answer is C

Step-by-step explanation:

* Lets talk about some facts in parallelograms and rectangles

- Rectangle is a parallelogram with right angles

- Supplementary angles is two angles their sum is 180°

- The opposite angles in the rectangle are equal and supplementary

- A circle can circumscribe a quadrilateral if the opposite angles of

the quadrilateral are supplementary

- In the parallelograms opposite angles are equal

- The circle can circumscribe a rectangle because its opposite

angles are supplementary

- The circle can't circumscribe a parallelogram because its opposite

angles are not supplementary they are equal

* Lets solve the problem

- Polygon A is a parallelogram

- Polygon B is a rectangle (parallelogram with right angles)

∵ The circle can't circumscribe a parallelogram because its opposite

angles are not supplementary

∴ Polygon A can't circumscribed by a circle

∵ Polygon B is a rectangle its opposite angles are equal the measure

of each one is 90°

∴ Its opposite angles are supplementary

∴ Polygon B can circumscribed by a circle

∵ The rectangle is a parallelogram with right angles

∴ Polygon B represents the only parallelogram that a circle can

circumscribed because opposite angles are supplementary

* The answer is C

6 0

3 years ago

The following value 1.23456789 x 10-6 what is a answer?

Amiraneli [1.4K]

Answer 1:

1.23456789 × (10-6) = 4.93827156

Answer 2:

(1.23456789 × 10) - 6 = 6.3456789

Answer 3:

1.23456789 × $10^{-6}$ = 0.000000123456789

Hope this helped! :)

4 0

2 years ago

50 points + brainliest

xxTIMURxx [149]

Solving this problem involves repeated application of the distance formula. In order to figure out which vertices we need to connect to another vertex, we should first plot the points on the coordinate plane to get an idea of what the polygon looks like. To form the sides of this polygon (which is, in our case, a pentagon), we'll need to connect the points in the following pairs:

(-2, -2) and (3, -3)
(3, -3) and (4, -6)
(4, -6) and (1, -6)
(1, -6) and (-2, -4)
(-2, -4) and (-2, -2)

In case you forgot, the distance formula is simply an application of the Pythagorean Theorem that treats the x-distance and y-distance between two points as the "legs" of a right triangle, and the shortest distance between them as the "hypotenuse."

If a and b are the legs of a right triangle, and c is the hypotenuse, the Pythagorean Theorem can be written as:

$a^2+b^2=c^2$

Or, if we're just looking for the value of c:

$c=\sqrt{a^2+b^2}$

Since the hypotenuse in our case represents distance, it's more descriptive to rename that variable d. Also, the "legs" a and b in this problem represent the distances between the x and y components of the two points. If we take any two points $(x_1,y_1)$ and $(x_2,y_2)$ , the distance between the x components of those points would be their difference, $x_2-x_1$ , and the distance between the y components would be $y_2-y_1$ . Substituting that all in, the distance formula becomes:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

All that's left to do now is substitute our specific points into the formula for each side of the polygon:

(-2, -2) and (3, -3):
$d=\sqrt{(3-(-2))^2+(-3-(-2))^2}\\ d=\sqrt{(3+2)^2+(-3+2)^2}\\ d=\sqrt{5^2+(-1)^2}\\ d=\sqrt{25+1}\\ d=\sqrt{26}\\ d\approx5.1$

(3, -3) and (4, -6)
$d=\sqrt{(4-3)^2+(-6-(-3))^2}\\ d=\sqrt{1^2+(-6+3)^2}\\ d=\sqrt{1+(-3)^2}\\d=\sqrt{1+9}\\ d=\sqrt{10}\\ d\approx3.2$

(4, -6) and (1, -6)
$d= \sqrt{(1-4)^2+(-6-(-6))^2} \\ d= \sqrt{(-3)^2+0^2} \\ d= \sqrt{9} \\ d=3$

(1, -6) and (2, -4)
$d= \sqrt{(2-1)^2+(-4-(-6))^2}\\ d= \sqrt{1^2+(-4+6)^2}\\ d= \sqrt{1+2^2}\\ d= \sqrt{1+4} \\ d= \sqrt{5}\\ d\approx2.2$

(2, -4) and (-2, -2)
$d= \sqrt{(-2-2)^2+(-2-(-4))^2}\\ d= \sqrt{(-4)^2+(-2+4)^2} \\ d= \sqrt{16+2^2}\\ d= \sqrt{16+4}\\ d= \sqrt{20} \\ d\approx4.5$

Rounding beforehand and adding up all of the distances gives us a perimeter of 18 units, which is remarkably close to the more precise approximation of 17.96 units. Given your options, 17.9 units would be the closest to the result we obtained here.

6 0

4 years ago

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