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3 years ago

What is the surface area of the rectangular prism below?

Mathematics

2 answers:

sergij07 [2.7K]3 years ago

9 0

Answer:

C. $736\text{ units}^2$

Step-by-step explanation:

We have been given an image of a rectangular prism. We are asked to find the surface area of our given prism.

$SA=2(lb+bh+hl)$ , where,

SA = Surface area,

l = Length,

h = Height,

b = Breadth.

Upon substituting $l=8$ , $h=8$ and $b=19$ in surface area formula, we will get:

$SA=2(8*19+19*8+8*8)$

$SA=2(152+152+64)$

$SA=2(368)$

$SA=736$

Therefore, the surface area of our given prism is 736 square units and option C is the correct choice.

ASHA 777 [7]3 years ago

7 0

Answer: The correct answer is C. 736 units²

Step-by-step explanation: The formula you must use to find the surface area of a rectangular prism is A = 2(wl + hl + hw) so to solve this particular equation you must solve 2(19x8 + 19x8 + 8x8)

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zlopas [31]

Step-by-step explanation:

transform the parent graph of f(x) = ln x into f(x) = - ln (x - 4) by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

0 = ln (x - 4)

$e^{0} = e^{ln (x - 4)}$

1 = x - 4

+4 +4

5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

1 = ln (x - 4)

$e^{1} = e^{ln (x - 4)}$

e = x - 4

+4 +4

e + 4 = x

6.72 = x

(6.72, 1)

Domain: x - 4 > 0

+4 +4

x > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ into f(x) = - 3ˣ⁺⁵ by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0. the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

= - 3⁰⁺⁵

= - 3⁵

= -243

Horizontal Asymptote: y = 0 (explanation above)