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Westkost [7]
3 years ago
8

An octet is formed via ionic bonding when one or more valence electrons are transferred from one atom to another. An octet is fo

rmed via covalent bonding when valence electrons are shared between atoms. True or false?
Physics
1 answer:
Elena L [17]3 years ago
6 0
<h2>The second statement is true.</h2>

Explanation:

"An octet is formed via covalent bonding when valence electrons are shared between atoms" this statement is true.

  • The ionic bond is formed when there is an overall transfer of valence electron among the two atoms that generates two oppositely charged ions. One atom loses electrons forming positively charged cation, other accepts the electrons forming a negatively charged anion hence octet can not be formed
  • In covalent bonding there is sharing of electrons hence an octet is formed

∴ The second statement is true.

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Which of the following happens to an object in uniform circular motion?
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Answer:

As an object moves in a circle, it is constantly changing its direction. ... Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction. An object undergoing uniform circular motion is moving with a constant speed.

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Suppose that the clay balls model the growth of a planetesimal at various stages during its accretion. Choose the planetesimal t
motikmotik

Answer:2

Explanation:

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4 years ago
The hydraulic oil in a car lift has a density of 8.53 x 102 kg/m3. The weight of the input piston is negligible. The radii of th
navik [9.2K]

Answer:

(a) the input force is 36.56 N

(b) the input force is 37.49 N

Explanation:

Given;

density of hydraulic oil, ρ =  8.53 x 10² kg/m³

radius of plunger, r₁ = 0.135 m

radius of piston, r₂ = 5.43 x 10⁻³ m

Part (a) The input force needed to support 22600-N weight, when the bottom surfaces of the piston and plunger are at the same level;

P =\frac{F}{A}

Where;

P is pressure

F is force

A is circular area = πr²

\frac{F_1}{A_1} =\frac{F_2}{A_2} \\\\F_2 = \frac{F_1*A_2}{A_1} =\frac{F_1* \pi r_2^2}{\pi r_1^2} = \frac{F_1*  r_2^2}{ r_1^2} \\\\F_2 = \frac{22600*(5.43*10^{-3})^2 }{(0.135)^2}\\\\F_2 = 36.56 \ N

Part (b) The input force needed to support 22600-N weight, when the  bottom surface of the output plunger is 1.20 m above that of the input plunger

P_2 = P_1 + \rho gh

But, F = PA  and  A = πr²

F_2 = F_1(\frac{A_2}{A_1} ) + \rho gh*A_2\\\\F_2 = F_1(\frac{r_2^2}{r_1^2} )+\rho gh(\pi r_2^2)\\\\F_2 = 22600(\frac{5.43*10^{-3}}{0.135})^2 \ + 853*9.8*1.2*\pi (5.43*10^{-3})^2\\\\F_2=36.56 + 0.93\\\\F_2 = 37.49 \ N

4 0
3 years ago
Most metals are in the liquid state at room temperature.
aivan3 [116]

Answer:

Most metals are in the liquid state at room temperature.<u>False</u><u>.</u>

Explanation:

it needs excess heat except mercury and lithium.

4 0
3 years ago
Read 2 more answers
A roller-coaster car has a mass of 1080 kg when fully loaded with passengers. As the car passes over the top of a circular hill
Dmitriy789 [7]

Answer:

(a): The normal force on the car  from the track when the car's speed is v= 7.6 m/s  is  FN= -6696 N.

(b): The normal force on the car from the track when the car's speed is v= 17 m/s is FN= 8912.7 N.

Explanation:

m= 1080 kg

r= 16m

v1= 7.6 m/s

v2= 17 m/s

g= 9.81 m/s²

v1= w1*r

w1= v1/r

w1= 0.475 rad/s

ac1= w1² * r

ac1= 3.61 m/s²

FN= m * (ac1 - g)

FN= -6696 N    (a)

-----------------------------------------------------

v2= w2*r

w2= v2/r

w2= 1.06 rad/s

ac2= w2² * r

ac2= 18.06 m/s²

FN= m * (ac2 - g)

FN= 8912.7 N    (b)

4 0
3 years ago
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