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Likurg_2 [28]
4 years ago
15

The relationship between charges can be described by saying,

Physics
2 answers:
Ostrovityanka [42]4 years ago
6 0

The correct answer for above statement is:

d.) opposite charges attract.

Explanation:

Electric charges are of two generic types: positive and negative. Two objects that have an abundance of one type of charge exercise a force of repellency on each other when comparatively close together. Two objects that have excess opposite charges, one positively charged and the other negatively charged, bring each other when approximately near.



umka21 [38]4 years ago
3 0
The relationship between charges can be described by saying that ) opposite charges attract.
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Given an electron beam whose electrons have kinetic energy of 10.0 kev , what is the minimum wavelength λmin of light radiated b
kolbaska11 [484]
To answer the problem we would be using this formula which isE = hc/L where E is the energy, h is Planck's constant, c is the speed of light and L is the wavelength 
L = hc/E = 4.136×10−15 eV·s (2.998x10^8 m/s)/10^4 eV 

= 1.240x10^-10 m 

= 1.240x10^-1 nm
3 0
4 years ago
Read 2 more answers
Two students of equal weight go from the first floor to the second floor. The first student uses an elevator and the second stud
Reil [10]

Answer: Option 3: THE SAME

Explanation:

The gravitational potential at a point or location is equal to the work per unit mass of a certain body that would be needed to move the body to that point from a reference point or location. The gravitational potential of both the first student that used the elevator and the second student that used the stairs are THE SAME because they both moved from referenced location (first floor) to the other location(second floor) and work is done per unit mass.

8 0
3 years ago
An object at 500 K dissipates 25.0 kJ of heat into the surroundings. What is the change in entropy ΔSΔSDeltaS of the object? Ass
Aloiza [94]

Answer:

Δ S = -50 J

Explanation:

given,

Temperature, T = 500 K

Heat dissipates, Q = 25.0 kJ

                            Q = 25000 J

change in entropy, ΔS = ?

using equation of entropy

 \Delta S = \dfrac{\Delta Q}{T}

 \Delta S = -\dfrac{25000}{500}

        Δ S = -50 J

negative sign is used because heat is lost in the surrounding.

Hence, Change in entropy is equal to -50 J

5 0
3 years ago
A person walks 2.00 m east, then turns and goes 4.00 m west, then turns and goes back 1.00m East
tangare [24]

Answer: what is the person’s distance

8 0
4 years ago
A candle is placed 14 cm in front of a concave mirror. The image of the candle is focused on a sheet of paper that is exactly 21
iris [78.8K]

Answer:

The magnification of the image is  M  = -1.5

Explanation:

From the question we are told that

      The object distance is  u = 14 cm

      The image distance is  v = 21 \ cm

The magnification of the image is mathematically represented as

        M  = -  \frac{v}{u}

substituting values

       M  = -  \frac{21}{14}

        M  = -1.5

The negative value means that the image is real , inverted and enlarged

8 0
4 years ago
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