Yes because mercury has more protons and electrons that tin. (30 more)
If its atomic number is 48, then it has 48 protons in the nucleus
of each atom. Any more mass than that is supplied by the neutrons
that are mixed in there with the protons.
If the mass is 167, and 48 of those are protons, then there are
(167 - 48) = 119 neutrons
in each nucleus.
This is an interesting (read tricky!) variation of Rydberg Eqn calculation.
Rydberg Eqn: 1/λ = R [1/n1^2 - 1/n2^2]
Where λ is the wavelength of the light; 1282.17 nm = 1282.17×10^-9 m
R is the Rydberg constant: R = 1.09737×10^7 m-1
n2 = 5 (emission)
Hence 1/(1282.17 ×10^-9) = 1.09737× 10^7 [1/n1^2 – 1/25^2]
Some rearranging and collecting up terms:
1 = (1282.17 ×10^-9) (1.09737× 10^7)[1/n2 -1/25]
1= 14.07[1/n^2 – 1/25]
1 =14.07/n^2 – (14.07/25)
14.07n^2 = 1 + 0.5628
n = √(14.07/1.5628) = 3
The answer to the question is that before the big bang, the universe was much hotter and more dense than it is now. Letter B.
It is because after the big bag occurred, the universe became cooler and less dense.
a. - does not correspond in the answer because the universe became less dense after the big bang.
c - the universe became cool and less dense after the big bang so being cool and less dense does not correspond to the question.
d - cooler does not answer the question because it only became cooler after the big bang.
Answer:
7808 m/s
Explanation:
Find NE velocity after 60 s of acceleration in that direction:
= a t = 28.4 m/s^2 * 60 s = 1704 m/s
Vertical component = 1704 sin 45 = 1204.9 m/s
Horiz component = 1704 cos 45 = 1204.9 m/s
Add the two vertical components
6510 + 1204.9 = 7714.9 m/s = vertical velocity
Pythagorean theorem to find resultant of vertical and horiz v's
Vf ^2 = 1204.9^2 + 7714.9^2 0
Vf = 7808. m/s
