Solution is given in following attachment.
The force between the two particles will quadruple
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
d is the separation between the two charges
In this problem, let's call F the initial force between the two charges, when they are at a distance of d.
Later, the distance between the two particles is halved, so the new distance is:
![d'=\frac{d}{2}](https://tex.z-dn.net/?f=d%27%3D%5Cfrac%7Bd%7D%7B2%7D)
This means that the new electrostatic force will be:
![F'=k\frac{q_1 q_2}{(d/2)^2}=4(k\frac{q_1 q_2}{d^2})=4F](https://tex.z-dn.net/?f=F%27%3Dk%5Cfrac%7Bq_1%20q_2%7D%7B%28d%2F2%29%5E2%7D%3D4%28k%5Cfrac%7Bq_1%20q_2%7D%7Bd%5E2%7D%29%3D4F)
Therefore, the force between the two particles will quadruple.
Learn more about electrostatic force:
brainly.com/question/8960054
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Explanation:
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<span>The gravitational force is 10 N down, and the force of air resistance is 1 N up.
The 1 N up exactly cancels one of the 10 N down.
What's left is the net force on the ball . . . . . 9 N down.</span>