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2 years ago

Data is information from which conclusions can be drawn.. . True. False

2 answers:

7 0

That statement is True.

Data will show you the element that you need to draw conclusion of your study/experiment.
For example, if after you gather the the data from 100 heart patient and 70 percent of them are obese, you can draw a conclusion that obesity is linked with heart disease

hope this helps

Nina [5.8K]2 years ago

5 0

You can draw conclusions from data, so it would be true

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A big box of sausages (30 kg) are lifted from the ground to the top shelf of the freezer. If the box is lifted at a constant spe

morpeh [17]

Answer:

The work done by gravity moving the box up is -514.5 Joules.

Explanation:

The gravity acts in the direction of the displacement, which in this case is negative (ground - top shelf), and so the resulting work is negative. The work is calculated as:

$W_g = mg\Delta h = 30kg\cdot 9.8\frac{m}{s^2}\cdot(0-1.75)m=-514.5J$

The work done by gravity moving the box up is -514.5 Joules.

4 0

2 years ago

A 326 g object is attached to a spring and executes simple harmonic motion with a period of 0.250 s. If the total energy of the

Basile [38]

Answer:

a) $v_{max}=5.98\frac{m}{s}$

b) $k=205.92\frac{N}{m}$

c) $A=0.24m$

Explanation:

a) In the equilibrium position of the system, that is when the spring is not elongated, the potential energy is zero. Therefore, the total energy of the system is the maximum kinetic energy:

$E=K_{max}\\E=\frac{mv_{max}^2}{2}\\v_{max}=\sqrt{\frac{2E}{m}}\\v_{max}=\sqrt{\frac{2(5.83J)}{0.326kg}}\\v_{max}=5.98\frac{m}{s}$

b) The force constant of the spring can be calculated from the natural frequency of the system:

$\omega^2=\frac{k}{m}\\k=m\omega^2$

Recall that $\omega=\frac{2\pi}{T}\\$ , that is the distance traveled in one revolution divided into the time of one revolution. Replacing and solving for k:

$k=\frac{m4\pi^2}{T^2}\\k=\frac{(0.326kg)4\pi^2}{(0.25s)^2}\\k=205.92\frac{N}{m}$

c) The maximum speed is directly proportional to the amplitude of the motion:

$v_{max}=A\omega\\A=\frac{v_{max}}{\omega}\\A=\frac{(v_{max})T}{2\pi}\\A=\frac{(5.98\frac{m}{s})0.25s}{2\pi}\\A=0.24m$

3 0

2 years ago

a car that is moving in a straight line has an acceleration of 8.0 m/s/s for 4.0 seconds. which one of the following is true of

Nuetrik [128]

Answer:

32 ms

Explanation:

v=32ms.

Explanation:

I will assume that you mean that the acceleration is 8.0 ms2, as 8.0ms is a value for velocity, not acceleration.

Here, we use the formula v=u+at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is time. Let's substitute values, then:

v=u+at,

v=0+8.0⋅4.0

v=32,

v=32ms.

Hope it Helps! :D .

7 0

2 years ago

As you approach your vehicle and perform checks it is not necessary to always

Greeley [361]

1.) Have your keys in hand before approaching or entering your car.

2. Be alert to other pedestrians and drivers.

3.) Search for signs of movement between, beneath and around objects to both sides of your vehicle

4.) check the spare tire for proper inflation

4 0

2 years ago

A circular curve of radius 150 m is banked at an angle of 15 degrees. A 750-kg car negotiates the curve at 85.0 km/h without ski

Crazy boy [7]

Answer: a) 7.1 * 10^3 N; b) -880 N directed out of the curve.

Explanation: In order to solve this problem we have to use the Newton laws, then we have the following:

Pcos 15°-N=0

Psin15°-f= m*ac

from the first we obtain N, the normal force

N=750Kg*9.8* cos (15°)= 7.1 *10^3 N

Then to calculate the frictional force (f) we can use the second equation

f=P sin (15°) -m*ac where ac is the centripetal acceletarion which is equal to v^2/r

f= 750 *9.8 sin(15°)-750*(85*1000/3600)^2/150= -880 N

6 0

2 years ago