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Svetlanka [38]
3 years ago
14

Data is information from which conclusions can be drawn.. . True. False

Physics
2 answers:
choli [55]3 years ago
7 0
That statement is True. 

Data will show you the element that you need to draw conclusion of your study/experiment.
For example, if after you gather the the data from 100 heart patient and 70 percent of them are obese, you can draw a conclusion that obesity is linked with heart disease

hope this helps
Nina [5.8K]3 years ago
5 0
You can draw conclusions from data, so it would be true
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Ask a member of the family to help you.Do the following activities and identify the skill/skills being excited . use a separate
Archy [21]

Answer:

Ok. Thanks.

I'll try it out.

3 0
2 years ago
A starship travels to a planet that is 20 light years away. The astronauts stay on the planet for 2.0 years before returning at
ad-work [718]

Answer:

astronauts age is 32 years

correct option is e 32 years

Explanation:

given data

travels = 20 light year

stay = 2 year

return = 52 years

to find out

astronauts aged

solution

we know here they stay 2 year so time taken in traveling is

time in traveling = ( 52 -2 )  = 50 year

so it mean 25 year in going and 25 years in return

and distance is given 20 light year

so speed will be

speed = distance / time

speed = 20 / 25 = 0.8 light year

so time is

time = \frac{t}{\sqrt{1-v^2} }

time =  \frac{25}{\sqrt{1-0.8^2} }

time = 15 year

so age is 15 + 2 + 15

so astronauts age is 32 years

so correct option is e 32 years

4 0
2 years ago
Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slid
nataly862011 [7]

Answer:

A)

the minimum stopping distance for which the load will not slide forward relative to the truck is 14 m

B)

data that were not necessary to the solution are;

a) mass of truck and b) mass of load

Explanation:

Given that;

mass of load m_{LS} = 10000 kg

mass of flat bed m_{FB} = 20000 kg

initial speed of truck v_{0} = 12 m/s

coefficient of friction between the load sits and flat bed μs = 0.5

A) the minimum stopping distance for which the load will not slide forward relative to the truck.

Now, using the expression

Fs,max = μs F_{N}     -------------let this be equation 1

where F_{N} = normal force = mg

so

Fs,max = μs mg

ma_{max} = μs mg

divide through by mass

a_{max} = μs g    ---------- let this be equation 2

in equation 2, we substitute in our values

a_{max} = 0.5 × 9.8 m/s²

a_{max} = 4.9 m/s²

now, from the third equation of motion

v² = u² + 2as

v_{f}² = v_{0}² + 2aΔx

where v_{f} is final velocity ( 0 m/s )

a is acceleration( - 4.9 m/s² )

so we substitute

(0)² = (12 m/s)² + 2(- 4.9 m/s² )Δx

0 = 144 m²/s² - 9.8 m/s²Δx

9.8 m/s²Δx = 144 m²/s²

Δx = 144 m²/s² /  9.8 m/s²

Δx = 14 m

Therefore, the minimum stopping distance for which the load will not slide forward relative to the truck is 14 m

B) data that were not necessary to the solution are;

a) mass of truck and b) mass of load

3 0
3 years ago
2. A 1750 kg car accelerates at a rate of 4.0 m/s2. How much force is the cars engine producing?
8090 [49]

Answer:

<h2>7000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1750 × 4

We have the final answer as

<h3>7000 N</h3>

Hope this helps you

6 0
3 years ago
You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten
charle [14.2K]

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

\mu = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}

So

f\propto \sqrt{\dfrac{1}{\mu}}

\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m

The mass density of the E string is 0.000507 kg/m

8 0
3 years ago
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