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statuscvo [17]
2 years ago
15

Use Table 1 below to answer the following question: Scientists find a piece of wood that is thought to be from an ancient fire c

ircle. They find that the wood contains an amount of carbon-14 (14C) that is approximately 1/16 of the current atmospheric C14 levels.
If you started with 1 million carbon-14 atoms, how many atoms would remain in the wood? C14 has a t1/2 of 5,750 years. (Only use numbers in your answer)

Chemistry
1 answer:
mrs_skeptik [129]2 years ago
6 0
Time passed    Time passed  14C initially present   14C at end of half-life
(half life)               (Years)
 ........................................................................................................................
     0                           0                           1,000,000                 1,000,000

     1                           5750                          .....                          5,00,000

     2                          11500                         .....                          2,50,000          

     3                          17250                         .....                          1,25,000
 
     4                           23000                        .....                            62,500

Since, wood sample contained 1/16 of current atmospheric concentration of 14C. It means that sample has crossed 4 half-life. Number atoms left are 4 half life = 62,500
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20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc
bezimeni [28]

Answer:

Concentration of the barium ions  = [Ba^{2+}] = 0.4654 M

Concentration of the chloride ions  = [Cl^{-}]=0.9308 M

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride  = 0.1355 M

n=0.1355 M\times  0.04389 L=0.005947 mol

Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

\frac{1}{2}\times 0.05947 mol=0.029735 mol barium hydroxide

Moles of barium hydroxide = 0.029735 mol

Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

=1\times 0.029735 mol= 0.029735 mol

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL  = 63.89 mL = 0.06389 L

Concentration of the barium ions =[Ba^{2+}]

[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M

Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M

8 0
3 years ago
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