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statuscvo [17]
3 years ago
15

Use Table 1 below to answer the following question: Scientists find a piece of wood that is thought to be from an ancient fire c

ircle. They find that the wood contains an amount of carbon-14 (14C) that is approximately 1/16 of the current atmospheric C14 levels.
If you started with 1 million carbon-14 atoms, how many atoms would remain in the wood? C14 has a t1/2 of 5,750 years. (Only use numbers in your answer)

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
6 0
Time passed    Time passed  14C initially present   14C at end of half-life
(half life)               (Years)
 ........................................................................................................................
     0                           0                           1,000,000                 1,000,000

     1                           5750                          .....                          5,00,000

     2                          11500                         .....                          2,50,000          

     3                          17250                         .....                          1,25,000
 
     4                           23000                        .....                            62,500

Since, wood sample contained 1/16 of current atmospheric concentration of 14C. It means that sample has crossed 4 half-life. Number atoms left are 4 half life = 62,500
You might be interested in
10.
Ugo [173]

Answer:

Density, \rho=24.68\ g/cm^3

Explanation:

Mass of a marble slab is 38.6 kg 38600 grams

The dimensions of the marble is 17 cm×23 cm×4 cm

We need to find its density. Mass per unit volume equals density. So,

\rho=\dfrac{m}{V}\\\\\rho=\dfrac{m}{lbh}\\\\\rho=\dfrac{38600\ g}{(17\times 23\times 4)\ cm^3}\\\\\rho=24.68\ g/cm^3

So, the density of the marble slab is 24.68\ g/cm^3

5 0
4 years ago
how many moles of potassium would you need to prepare 1200 grams of 5.0% potassium sulfate (m/m) solution
Marianna [84]
The  moles  of  potassium  that  you  would    need  to  prepare  1200 g  of  5% potassium   sulfate solution  is    1.538 moles

calculation
  calculate  the mass  potassium using  the below formula

%M/M =  mass  of the  solute(potassium)/mass of the  solvent (potassium  sulfate solution)

let  the  mass  of  potassium be represented by  Y

then  convert %  into fraction  = 5/100

5/100 =  Y/1200
cross  multiplication
100y =  6000
divide  both side by 100

Y=  60 g

moles of potassium =mass/molar  mass

= 60/39=1.538
7 0
4 years ago
This liquid metal has more protons than gold, but fewer electrons then thallium.
WITCHER [35]

The number of protons and electrons of an atom is equal and the amount can be obtained by looking at the atomic number of that atom or element.

The atomic numbers are:

Gold = 79

Thallium = 81

 

So we are looking for the element with an atomic number of 80, that is:

Mercury

 

Answer:

<span>Mercury (Hg)</span>

4 0
3 years ago
A partir de lo propuesto por Bohr en 1913, que postulado es correcto:
TEA [102]

Answer:

Primer postulado:

Así Bohr asumió que el átomo de hidrógeno puede existir solo en ciertos estados discretos, los cuales son denominados estados estacionarios del átomo. En el átomo no hay emisión de radiación electromagnética mientras el electrón no cambia de órbita.

Explanation:

4 0
3 years ago
3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O
Ksivusya [100]

Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

<h3 /><h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

  • Cu: 3 moles
  • HNO₃: 8 moles
  • Cu(NO₃)₂: 3 moles
  • NO: 2 moles
  • H₂O: 4 moles

<h3>Amount of moles of NO produced</h3>

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}

<u><em>amount of moles of NO= 6.75 moles</em></u>

In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

Learn more about reaction stoichiometry:

<u>brainly.com/question/11999193</u>

<u>brainly.com/question/15111313?referrer=searchResults</u>

<u>brainly.com/question/9926203?referrer=searchResults</u>

<u>brainly.com/question/6061451?referrer=searchResults</u>

4 0
3 years ago
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