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Lottery Number Generator Design a program that generates a 7-digit lottery number. The program should have an Integer array with

Nikolay [14]

Answer:

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#include <iostream>

#include <string>

#include <sstream>

using namespace std;

bool equal(int sys[],int user[])

{

for (int i=0;i<7;i++)

{

if(sys[i]!=user[i]){

return false;

}

return true;

}

int main()

{

int sys[7];

int user[7];

int min=0

;int max=9;

string userinput;

while(0==0){

for (int i=0;i<7;i++)

{

sys[i]=rand() % (max - min + 1) + min;

}

cout <<endl;

cout<<"enter numbers"<<endl;

for (int i=0;i<7;i++)

{

getline (cin,userinput);

if(userinput=="x"){

return 0;

}

else{

stringstream(userinput) >> user[i];

}

cout<<"User number"<<endl;

for (int i=0;i<7;i++)

{

cout << user[i];

}

cout<<"system number"<<endl;

for (int i=0;i<7;i++)

{

cout << sys[i];

}

if(equal(sys,user))

{

cout<<"You won !"<<endl;

}else {

cout<<"Try again :("<<endl;

}

return 0;

}

Explanation:

Using c++ rand function generate a random number between 0-9.

Formula for random number is rand (max-min +1)+min.

Run this in a loop for 7 time and store each number to an array index in sys array which is for system generated number.

now using string take input from user and check if input is x close program else use stringstream to parse input string to int and store it in user array. Stringstream is a cpp header file used for parsing and handling of strin g inputs. Run this program in loop for 7 times.

Now create a function of type boolean denoted by "bool". This will take both arr as parameter and check if both are equal or not. It compares eac index of user array against each index of sys array and if both values are not equal returns false.

5 0

3 years ago

What is the missing term in the code that handles that error??

kykrilka [37]

Answer:

try typing that into gooy gle im sorry if i didnt help

if tickets >400 What is the missing term in the code that handles that error??wat over400error

Explanation:

3 0

3 years ago

Which type of cell references are locked and NOT automatically updated when it’s copied

dsp73

Hi I would have to say B sorry if this answer is sucky but I'm trying my best to help you :D

4 0

3 years ago

You want to substitute one word with another throughout your

Hitman42 [59]

I’m pretty sure it’s “Find and paste”

8 0

3 years ago

Computer Networks - Queues

lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time $T_w$ in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w = λ × T_w

r / λ = w / λ + ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s $= \dfrac{1000}{64*1000}$

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05 (i.e the average packet waiting time)

T_s = 0.015625

T_r = 0.05 + 0.015625

T_r = 0.065625

However; the mean number of arrival per second λ is;

r = λ × T_r

λ = r / T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus; the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets w waiting to be served is calculated using the formula

w = λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0

3 years ago