Answer:
The length of side AC is 5 units.
The areas of triangle ABC is 10 square units.
Step-by-step explanation:
From point A (1,3) to point C (1,-2) is 5 units
To check this:
3 - (-2) = 3 + 2 =5
We're subtracting since the point went down (from positive 3 to negative 2)
Now for the area:
Area formula for a triangle:
bh =
⋅b⋅h
We already found the height (length) : 5
The base is from point C (1,-2) to point B (5,-2), which is 4 units
To check this:
5 - 1 = 4
Now that we have found the base and height, Let's solve:
⋅4⋅5 =
⋅20 = 10
Our area is 10 square units.
Hope that helps :)
K = s + 4
k + s = 26
s + 4 = 26
Subtract 4 from both sides of the equation.
s = 22
Steve ran 22 miles.
There is no answer because there cannot be one to one function inverse.
Factor out -4
-4(x^3+3x^2-2x-6
Factor out x^2
-4(x^2(x+3)-2x-6)
Factor out -2
-4(x^2(x+3)-2(x+3))
Factor out x+3
-4(x+3)(x^2-2)
4 1/3 = 13/3 = 1/3 x 13/1 = 4 1/3